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SpyIntel [72]
2 years ago
13

Meg made 3 gallons of lemonade for a group of campers. if each camper gets 1 cup of lemonade, how many campers can have lemonade

?
A. 16
B. 26
C. 48
D. 60
Mathematics
2 answers:
Elden [556K]2 years ago
8 0
1 gallon = 16 cups

3 x 16 = 48, so 48 campers can have lemonade :D

the answer is C)

hope this helps :)
Sonbull [250]2 years ago
7 0

Answer:

C

Step-by-step explanation:

1 gallon = 16 cups

3 gallons = 48 cups if each camper gets one cup of lemonade, it can serve 48 campers.

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Suppose that one wishes to schedule vehicles from a central depot to five customer locations. The distance of making trips betwe
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Answer:

The routing suggested by the savings method is route (3,4)

Step-by-step explanation:

Savings for all trips (i, j), 1 ≤ i ∠ j ≤ 5

Total  number of trips to be commuted = 10 trips

S₁₂ = C₀₁ + C₀₂ - C₁₂ = 20 + 75 - 35 = 60

S₁₃ = C₀₁ + C₀₃ - C₁₃ = 20 + 33 - 5 = 48

S₁₄ = C₀₁ + C₀₄ - C₁₄ = 20 + 10 - 20 = 10

S₁₅ = C₀₁ + C₀₅ - C₁₅ = 20 + 30 - 15 = 35

S₂₃ = C₀₂ + C₀₃ - C₂₃ = 75 + 33 - 18 = 90

S₂₄ = C₀₂ + C₀₄ - C₂₄ = 75 + 10 - 58 = 27

S₂₅ = C₀₂ + C₀₅ - C₂₅ = 75 + 30 - 42 = 63

S₃₄ = C₀₃ + C₀₄ - C₃₄ = 33 + 10 - 40 = 3

S₃₅ = C₀₃ + C₀₅ - C₃₅ = 33 + 30 - 20 = 43

S₄₅= C₀₄ + C₀₅ - C₄₅ = 10 + 30 - 25 = 15

3 0
3 years ago
For the function f(t) =Pe^rt , if P= 7 and r= 0.07 then what is the value of f(7) to the nearest tenth?
White raven [17]

Answer:

A. 11.4  

Step-by-step explanation:

f(t) = P e^{rt}

Data:

P = 7

r = 0.07

Calculation:

\begin{array}{rcl}f(t) & = &Pe^{rt}\\f(7)& = & 7 e^{(0.07 \times 7)}\\ & = & 7 e^{0.49}\\& \approx & 7 \times 1.632\\ & \approx & \mathbf{11.4}\\\end{array}

8 0
2 years ago
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May someone please help me please? This is about exponents by the way. About 5 questions I need help with.
Sloan [31]

Answer:

2x2x2x2x2x2x2=8/3=1 2/3

8x8x8=512

1/6x1/6x1/6= 1/216

5/8x5/8=1 2/8

Step-by-step explanation:

i hope this helps

have a nice day/night

mark brainliest, please :)

6 0
2 years ago
What is the step of it
andrew11 [14]
-9/3 + 4

-3 + 4 = 1

The answer to the question
7 0
3 years ago
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David will spend at most $39 on gifts. So far, he has spent $22. What are the possible additional amounts he will spend? Use c f
iren2701 [21]

Answer:

c\leq \$17

Step-by-step explanation:

Let

c -----> the additional amount (in dollars) David will spend

we know that

The word " at most" in this context means "less than or equal to"

The amount David has spent plus possible additional amounts he will spend must be less than or equal to $39

so

The inequality that represent this situation is

22+c\leq 39

solve for c

subtract 22 both sides

c\leq 39-22

c\leq \$17

The maximum amount he could spend is $17

7 0
2 years ago
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