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4 years ago

Which of the following phases has a variable volume?

Physics

2 answers:

stepan [7]4 years ago

6 0

Its B hope this helps. :)

hram777 [196]4 years ago

4 0

The answer would be B.

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Explain the difference between how intrusive and extrusive igneous rock form and how those formation processes affect the minera

rusak2 [61]

Extrusive molten rocks are formed from lava while the intrusive molten rocks are formed from magma.

Explanation:

Extrusive molten rocks originate from lava, framing at the outside of the Earth and cooling rapidly, which means they structure little precious stones. Intrusive volcanic rocks originate from magma, shaping profound underground and taking more time to cool, which means they structure bigger crystals.

Intrusive molten rocks are framed when magma cools gradually underneath the surface, while extrusive rocks are shaped when magma cools quickly at the surface.

6 0

4 years ago

Llus

ivann1987 [24]

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8 0

3 years ago

Read 2 more answers

Kamila [148]

Answer: (x - 4)² + (y - 7)² = 9

Explanation:

The equation of a circle is: (x - h)² + (y - k)² = r² where

(h, k) is the center
r is the radius

Given: (h, k) = (4, 7)

Find the intersection of the given equation and the perpendicular passing through (4, 7).

3x - 4y = -1

-4y = -3x - 1

$y=\dfrac{3}{4}x-1$

$m=\dfrac{3}{4}$ --> $m_{\perp}=-\dfrac{4}{3}$

$y-y_1=m_{\perp}(x-x_1)\\\\y-7=-\dfrac{4}{3}(x-4)\\\\\\y=-\dfrac{4}{3}x+\dfrac{16}{3}+7\\\\\\y=-\dfrac{4}{3}x+\dfrac{37}{3}$

Use substitution to find the point of intersection:

$x=\dfrac{29}{5}=5.8,\qquad y=\dfrac{23}{5}=4.6$

Use the distance formula to find the distance from (4, 7) to (5.8, 4.6) = radius

$r=\sqrt{(5.8-4)^2+(4.6-7)^2}\\\\r=\sqrt{3.24+5.76}\\\\r=\sqrt9\\\\r=3$

Input h = 4, k = 7, and r = 3 into the circle equation:

(x - 4)² + (y - 7)² = 3²

(x - 4)² + (y - 7)² = 9

4 0

3 years ago

The gravitational field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit t

3241004551 [841]

Answer:

$g'=\frac{g__R}{4}$

Explanation:

Given:

gravitational field strength of moon at a distance R from its center, $g__R$

Distance of the satellite from the center of the moon, $h=2R$

Now as we know that the value of gravity of any heavenly body is at height h is given as:

$g'=g__{R}} \times \frac{R^2}{(2R)^2}$

$g'=\frac{g__R}{4}$

∴The gravitational field strength will become one-fourth of what it is at the surface of the moon.

6 0

3 years ago

How can wind put off fire?

kipiarov [429]

♥ If the wind is strong enough it can do so.
♥ By having a strong enough wind you can blow out the fire before the flame can consume any more vapor.
♥ If the wind is fast enough, like a birthday cake candle for example, the wind will burn out.

7 0

3 years ago

Read 2 more answers