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Natasha2012 [34]
2 years ago
8

When exposed to a radioactive source which emits 1.2-MeV gamma-rays, a particular material is found to have a half-value thickne

ss X of 10 cm How thick would a shield made of this material need to be in order to block 75% of the radiation? A. 5 cm B. 20 cm C. 15 cm D. 25 cm E. 10 cm
Physics
1 answer:
iren2701 [21]2 years ago
4 0

Answer:E

Explanation:

It is given that Energy of gamma ray is E=1.2 Mev

Shielding effect can be measured by measuring the fraction of gamma rays blocked by shield. If certain thickness will able to block half the radiation then to block 75% radiation we need to add same amount of thickness in order to block the remaining radiation.

i.e. \frac{E}{2} fraction is blocked by 10 cm thickness

then remaining radiation is \frac{E}{2}

another 10 cm thickness will block the remaining half radiation i.e. \frac{1}{2}\times \frac{E}{2}=\frac{E}{4}

so total 75 % radiation will be blocked

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Answer:

time will elapse before it return to  its staring point is 23.6 ns

Explanation:

given data

speed u = 2.45 × 10^{7} m/s

uniform electric field E = 1.18 × 10^{4} N/C

to find out

How much time will elapse before it returns to its starting point

solution

we find acceleration first by electrostatic force that is

F = Eq

here

F = ma by newton law

so

ma = Eq

here m is mass , a is acceleration and E is uniform electric field and q is charge of electron

so

put here all value

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use equation of motion

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time will elapse before it return to  its staring point is 23.6 ns

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