Answer:
See explanation
Step-by-step explanation:
We want to verify that:

Verifying from left, we have

Expand the perfect square in the right:

We expand to get:

We simplify to get:

Cancel common factors:

This finally gives:

.76 cents per cup.
Their are 16 cups in a gallon.
2 gallons would be 32cups.
Divide 24.32 by 32.
0.76 is your answer
Answer:
A or 24
Step-by-step explanation:
In PEMDAS you do the steps from left to right in the name.
So first, you do 3 * x and x = 6 so 3 * 6 which is 18.
then 18 + y and y = 8 so 26
26 minus 2 is 24.
Hope this helped~ ^-^