0.044 M is the molarity of 1.60 L of a solution containing 8.53 g of dissolved KBr.
Explanation:
Data given:
volume of the solution = 1.60 litres
mass of KBr = 8.53 grams
atomic mass of KBr = 119.002 gram/moles (K = 39.09 g/mole + 79.9 g/mole)
number of moles =?
molarity of KBr solution =?
First the number of moles will be calculated by using the formula:
number of moles = 
putting the values in the equation:
number of moles = 
number of moles = 0.071 moles of KBr
now molarity is calculated using the formula:
molarity = 
putting the values in the equation:
molarity = 
= 0.044 M
molarity of KBr solution is 0.044 M
Answer: chlorine gas
Explanation:
mass = 0.508 g volume = 0.175 L
From ideal gas equation.
PV = nRT
(1.0 atm) × (0.175 L) = n × [0.0821 atm L / (mol K)] × [(273.2 + 25.0) K]
n = 1.0 × 0.175 / (0.0821 × 298.2) mol
n = 0.00715 mol
Molarmass= mass/mole
Molar mass of the gas = (0.508 g) / (0.00715 mol) = 71.0 g/mol
The molar mass of Cl₂ (chorine) = 35.5 × 2 g/mol = 71.0 g/mol
Hence, the gas is chlorine.
B. Solid water conforms to the shape of its container.
Answer:
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Explanation: