Question

2 points) Now they feel it is best to have you identify an unknown gas based on its properties. Suppose 0.508 g of a gas occupies a volume of 0.175 L at a temperature of 25.0◦C is held at a pressure of 1.000 atm. What gas is this most likely?

Answer 1

Answer: chlorine gas

Explanation:

mass = 0.508 g volume = 0.175 L

From ideal gas equation.

PV = nRT

(1.0 atm) × (0.175 L) = n × [0.0821 atm L / (mol K)] × [(273.2 + 25.0) K]

n = 1.0 × 0.175 / (0.0821 × 298.2) mol

n = 0.00715 mol

Molarmass= mass/mole

Molar mass of the gas = (0.508 g) / (0.00715 mol) = 71.0 g/mol

The molar mass of Cl₂ (chorine) = 35.5 × 2 g/mol = 71.0 g/mol

Hence, the gas is chlorine.