Answer:
Kc = 1.4752
Explanation:
- CH4 (g) + 2H2O (g) ↔ CO2 (g) + 4H2 (g)
⇒ Kc = ( [ CO2(g) ] * [ H2 ]∧4 ) / ( [ CH4 ] * [ H2O ]² )
∴ [ CO2 ] = ( 8.01 g * ( mol / 44.01 g ) ) / 1.5 L
⇒ [ CO2 ] = 0.1213 M
⇒ [ H2O ] = 0.877 mol / 1.5 L = 0.585 M
⇒ [ CH4 ] = 0.380 mol / 1.5 L = 0.253 M
⇒ [ H2 ] = (( 0.380 mol CH4 ) * ( 4 mol H2 / mol CH4 )) / 1.5 L = 1.013 M
⇒ Kc = (( 0.1213 ) * ( 1.013 )∧4 ) / (( 0.253 ) * ( 0.585 )² )
⇒ Kc = 1.4752
Answer:
![2.4\times 10^{-8} C](https://tex.z-dn.net/?f=2.4%5Ctimes%2010%5E%7B-8%7D%20C)
Explanation:
We are given that
Distance between two tiny particles=d=1mm=![1\times 10^{-3} m](https://tex.z-dn.net/?f=1%5Ctimes%2010%5E%7B-3%7D%20m)
Force,F=5 N
We have to find the magnitude of the charge on each of these particles.
Let charge on each particle=q
By Coulomb's law of force
![F=\frac{kq_1q_2}{r^2}=\frac{kq^2}{r^2}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7Bkq_1q_2%7D%7Br%5E2%7D%3D%5Cfrac%7Bkq%5E2%7D%7Br%5E2%7D)
Where ![k=9\times 10^9](https://tex.z-dn.net/?f=k%3D9%5Ctimes%2010%5E9)
Substitute the values
![5=\frac{9\times 10^9q^2}{(1\times 10^{-3})^2}](https://tex.z-dn.net/?f=5%3D%5Cfrac%7B9%5Ctimes%2010%5E9q%5E2%7D%7B%281%5Ctimes%2010%5E%7B-3%7D%29%5E2%7D)
![q^2=\frac{5\times (1\times 10^{-3})^2}{9\times 10^9}](https://tex.z-dn.net/?f=q%5E2%3D%5Cfrac%7B5%5Ctimes%20%281%5Ctimes%2010%5E%7B-3%7D%29%5E2%7D%7B9%5Ctimes%2010%5E9%7D)
![q=\sqrt{\frac{5\times (1\times 10^{-3})^2}{9\times 10^9}}](https://tex.z-dn.net/?f=q%3D%5Csqrt%7B%5Cfrac%7B5%5Ctimes%20%281%5Ctimes%2010%5E%7B-3%7D%29%5E2%7D%7B9%5Ctimes%2010%5E9%7D%7D)
![q=2.4\times 10^{-8} C](https://tex.z-dn.net/?f=q%3D2.4%5Ctimes%2010%5E%7B-8%7D%20C)
1, When temperature is increased the volume will also increase. this is because the particles will gain kinetic energy and bombard the walls of the container of the gas at a higher frequency, therefore, for the pressure to remain constant as per Charles' law, the volume will have to increase so that the rate of bombardment remains constant. This is explained by the Charles law which states that the volume of a gas is directly proportional to the absolute temperature provided pressure remains constant.
2. When temperature is Decreased the volume will also Decrease. this is because the particles will loose kinetic energy and bombard the walls of the container of the gas less frequently, therefore, for the pressure to remain constant as per Charles' law, the volume will have to reduce so that the rate of bombardment remains constant. This is explained by the Charles law which states that the volume of a gas is directly proportional to the absolute temperature provided pressure remains constant.
3. When temperature is increased the pressure will increase. This is because the gas particles gain kinetic energy and bombard the walls of the container more frequently. this is according to Pressure law which states that for a constant volume of a gas the pressure is directly proportional to absolute temperature
4. When temperature is decreased, pressure will decrease, This is because the gas particles lose kinetic energy and bombard the walls of the container less frequently. this is according to Pressure law which states that for a constant volume of a gas the pressure is directly proportional to absolute temperature
5. When particles are added, pressure will increase. This is because the bombardment per unit area also increases. Boyles law explains this, that at fixed temperature the volume of a gas is inversely proportional to the pressure.
6. When particles are removed, the pressure will decrease. This is because the bombardment per unit area also decreases. Boyle's law explains this, that at fixed temperature the volume of a gas is inversely proportional to the pressure.
Answer:
Three times with 5 ml will yield more
Explanation:
Let x represent the amount yield
Kd = (x/15) / ((50-x) / 15) where Kd = 1.5
1.5 = (x/15) / ((50-x) / 15)
x / (50 - x) = 1.5
x = 75 - 1.5x
x + 1.5x = 75
2.5x = 75
x = 75 / 2.5 = 30 mg
when extraction three times
1st extraction
(x1/5) / ((50 - x1) / 15) = 1.5
3x1 / 50 - x1 = 1.5
3x1 = 75 - 1.5x1
3x1 + 1.5x1 = 75
4.5x1 = 75
x1 = 75 / 4.5 = 16.67 gm
second extraction
(x2/ 5) / (33.33 - x2 ) / 15) = 1.5
3x2 / ( 33.33 - x2) = 1.5
3x2 = 1.5(33.33 - x2)
3x2 = 49.995 - 1.5x2
3x2 + 1.5x2 = 49.995
4.5x2 = 49.995
x2 = 49.995 / 4.5
x2 = 11.11 mg
Third extraction
(x3/5) / ((22.22 - x3) / 15) = 1.5
3x3 = 1.5 ( 22.22 - x3)
3x3 + 1.5x3 = 33.33
4.5x3 = 33.33
x3 = 33.33 / 4.5 = 7.41 mg
total extraction = x1 + x2 + x3 =16.67 + 11.11 + 7.41 = 35.19 mg
the three times extraction using 5ml yields 5.19 mg more