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Lostsunrise [7]
3 years ago
11

Rectangle EFGH is rotated 90° clockwise around the origin. What are the coordinates of the image point F?

Mathematics
2 answers:
denpristay [2]3 years ago
4 0

Answer:

3 -5 on edg

Step-by-step explanation:

stealth61 [152]3 years ago
3 0

Answer: 3 -5

Step-by-step explanation:

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Which of the following graphs of exponential functions corresponds to a geometric sequence with a first term of 4 and a ratio of
ser-zykov [4K]

Answer: graph E.


A geometric sequence can be written as:

a_{n} = a_{1} \cdot r^{(n - 1)}

where:

a₁ = first term = 4

r = ratio = 0.5


Substituting the numbers, we have:

a_{n} = 4 \cdot (\frac{1}{2})^{n-1}

or else

f(x) = 4 \cdot (\frac{1}{2})^{x - 1}


This is an exponential function with base less than 1. Therefore, we can exclude graph C (which depicts a linear function), and graphs A and D (which depict an exponential function with base greater than 1).


In order to choose between graph B and E, let's evaluate the function in two different points:

f(1) = 4 \cdot (\frac{1}{2})^{1 - 1} = 4

f(2) = 4 \cdot (\frac{1}{2})^{2 - 1} = 4 \cdot \frac{1}{2} = 2


Therefore, we need to look for the graph passing through the points (1, 4) and (2, 2). That is graph E.




3 0
3 years ago
Read 2 more answers
Someone pls help! <br> write the expression in radical form. 2 4/5
kipiarov [429]

Answer:

  \sqrt[5]{2^4}

Step-by-step explanation:

Maybe you want 2^(4/5) in radical form.

The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.

  2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}

__

In many cases, it is preferred to keep the power inside the radical symbol.

7 0
3 years ago
Given: ZBECis a right angle<br> Prove: ZAEB and ZCED are complementary
MrRissso [65]
2x77}{x} theis way is the best answee
8 0
3 years ago
6) 6n+ 3 = 3(-7n + 1)<br> what did you guys get for the answer?
Allushta [10]

Answer:

n=0

Step-by-step explanation:

Clear parenthesis w/ distribution:

3(-7n+1)=-21n+3

Move everything over to one side:

6n+3=-21n+3

6n=21n                                                   Subtract the 3 on the right.

-15n=0                                                                      Subtract the 21.

n=0                                                                              Divide the -15.

5 0
3 years ago
Read 2 more answers
An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with
AleksandrR [38]

Answer:

U₂₁ and U₂₂ fits in the line of upper triangular

Step-by-step explanation:

As explain in the question

An upper triangular matric is square matrix with all zeros below its daignal. A lower triangular matrix is a square matrix with all zeros above its diagonal.

(as shown in the attached image)

(a)for all 3×3 upper triangular matirices U, verify that U2 is also upper triangular

for a matrices U (having a 3*3 matrix), assuming for example, U is given below:

U = \left[\begin{array}{ccc}1&2&3\\0&5&6\\0&0&9\end{array}\right]

the element in the upper triangular are 1,2,3,5,6,9 (U₁₁, U₁₂, U₁₃; , U₂₂, U₂₃, U₂₂)

while lower triangular are 0,0,0, the element in the lower triangular are (U₂₁, U₃₁,U₃₂)

U₂₁ and U₂₂ fits in the line of upper triangular

8 0
3 years ago
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