TRUE.THEY DO NOT COTAIN THOSE THINGS.
Answer:
Option D- frequency of the heterozygous qenotype
Explanation:
In the Hardy-Weinberg equilibrium , 2pq stands for the genotype frequency of heterozygotes (Aa) in a population at the state of equilibrium. dominant homozygotes (AA) is represented by the p-square and q- square represents the recessive homozygotes (aa) frequency. p represents the allele frequency of A Allele and q stands for the allele frequency of the allele a. Summation of the terms gives an equal to 1(100%). The sum of all of these terms is always equal to due to the fact that the 3 frequencies in the equation are the available or possible allele combinations.
Hardy-Weinberg is relevant for it helps us in comparison of a population's actual genetic structure as time goes on along with the genetic structure we are to get if really population was in Hardy-Weinberg equilibrium state that is population was not evolving.
Answer:sponge is one answer.
Explanation:
Although there is no attachment, the best answer would be option B.
DNA replication occurs in opposite directions along a strand of DNA.
The leading strand is replicated continuously in the 5' to 3' direction towards the replication fork.
The lagging strand is replicated discontinuously in the 5' to 3' with segments of DNA known as Okazaki fragments.
