If you do long division youll get the remainder which is: 28x + 30
we are given
airthematic sequence
we can use nth term formula

n is number of terms
an is nth term
d is common difference
a1 is first term
We are given
a7=40
we can use it



a18 = 106


we can subtract both equations



now, we can find a1

we can plug d=6


12th term:

now, we can plug values



so, 12th term is 70...........Answer
Answer:
11. This is counting only odd numbers, or counting by two starting with one.
Answer:
In every 42 days, Sherman and Brad will go golfing on the same day.
Step-by-step explanation:
Given:
Sherman goes golfing every 6th day.
Brad goes golfing every 7th day.
If they both went golfing today, we need to determine how many days unit they will go golfing on the same day again.
Solution:
In order to determine how many days unit Sherman and Brad will go golfing on the same day again, we will take least common multiple of 6 and 7.
To find least common multiple of 6 and 7, we will list out their multiples.


We find out that the least common multiple of 6 and 7 =42.
Thus, we can conclude that Sherman and Brad will go golfing on same days on every 42nd day after they meet..
Answer:
11, 60.61
Step-by-step explanation:
this is the only set that fits a^2 +b^2=c^2
you square the first two numbers, add them together. Then you take the square root of that sum. This number must equal the third number for it to be a triple.