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shusha [124]
3 years ago
13

Help with math homework pls! NO WRONG ANSWERS!!!

Mathematics
1 answer:
Masteriza [31]3 years ago
4 0

We have been given the expression

\frac{a\cdot a \cdot a \cdot a \cdot a \cdot a }{a}

We have to write this expression in the form a^n

In order to write the given expression in this form, we can use some exponent property.

(1) x^a\cdot x^b= x^{a+b}\\\\(2)\frac{x^a}{x^b}=x^{a-b}

On using the property (1), we have

\frac{a\cdot a \cdot a \cdot a \cdot a \cdot a }{a}\\\\=\frac{a^{1+1+1+1+1+1}}{a}\\\\\frac{a^6}{a}

Now, on using the property (2), we get

\frac{a^6}{a}\\\\=a^{6-1}\\\\=a^5

Therefore, the simplified form of the given expression is

a^5

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Let f(x) = log(x). Find values of a such that f(kaa) = kf(a).
meriva

Answer:

a = k^{\frac{1}{k-2}}

Step-by-step explanation:

Given:

f(x) = log(x)

and,

f(kaa) = kf(a)

now applying the given function, we get

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or

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Now, we know the property of the log function that

log(AB) = log(A) + log(B)

and,

log(Aᵇ) = b × log(A)

Thus,

⇒ log(k) + log(a²) = k × log(a)         (using log(AB) = log(A) + log(B) )

or

⇒ log(k) + 2log(a) = k × log(a)            (using log(Aᵇ) = b × log(A) )

or

⇒ k × log(a) - 2log(a) = log(k)

or

⇒ log(a) × (k - 2) = log(k)

or

⇒ log(a) = (k - 2)⁻¹ × log(k)

or

⇒ log(a) = \log(k^{\frac{1}{k-2}})          (using log(Aᵇ) = b × log(A) )

taking anti-log both sides

⇒ a = k^{\frac{1}{k-2}}

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What is -5 considered as
IceJOKER [234]
A negative Number, Hope this helped.
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3 years ago
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Fantom [35]

Answer:

StartFraction 25 Over 9 EndFraction

Step-by-step explanation:

\bigg(  \huge{\frac{ {3}^{2}a ^{ - 2}  }{3 {a}^{ - 1} }} \bigg)^{k}  \\  \\  =  \bigg(  \huge{\frac{ 9a   }{3 {a}^{ 2} }} \bigg)^{k}  \\  \\  = \bigg(  \huge{\frac{ 3   }{ {a}}} \bigg)^{k}  \\  \\  = \bigg(  \huge{\frac{ 3   }{ {5}}} \bigg)^{ - 2}   \\  \\  = \bigg(  \huge{\frac{ 5   }{ {3}}} \bigg)^{ 2}  \\  \\  =   \huge{\frac{ 25   }{ {9}}}

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