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Leona [35]
3 years ago
8

A group of friends is addressing wedding invitations. Casey can address 22 envelopes in one hour, Anne can address 46 envelopes

in two hours, and Paula can address 70 envelopes in three hours. About how long will it take them to address 450 envelopes?
A. 19.57 hours
B. 23.00 hours
C. 7.34 hours
D. 6.59 hours
Mathematics
2 answers:
DENIUS [597]3 years ago
7 0

Answer:

D. 6.59 hours

Step-by-step explanation:

First, divide 46 by 2.

46 / 2 = 23

Next, divide 70 by 3.

70 / 3 = 23.3333333... (rounded to 23.33)

Then, add them together and multiply by 6.59.

22 + 23 + 23.33 = 68.33

68.33 * 6.59 = 450.2947

Round it to the nearest ones place, and you get 450.

stepan [7]3 years ago
5 0

Answer:

6.30

Step-by-step explanation:

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elena55 [62]

Answer:

(4, -5)

(3, -2)

7 0
2 years ago
Determine the value of the variable. 5 + 17 = J - 14
Nataly_w [17]
You would add 5 and 17 and that would equal 22
Now it would be 22=J-14
Then add 14 on both sides so it cancels out 22 plus 14 is 36
So J would equal 36
3 0
2 years ago
Read 2 more answers
(0.3d-1.5)/3 1/3=0.84:7/15
Anika [276]

Answer:

  d = 25

Step-by-step explanation:

Perhaps you want to solve for d:

  (0.3d -1.5)/(3 1/3) = 0.84/(7/15)

Change the division by a fraction to multiplication by its inverse.

  (0.3d -1.5)·(3/10) = (0.84)·(15/7)

  0.09d -0.45 = 1.8 . . . . . . . . . . . . simplify

  d - 5 = 20 . . . . . . . . . . . . . . . . . . divide by 0.09

 d = 25 . . . . . . . . . . . . . . . . . . . . . add 5

_____

Grouping symbols help show what is being divided by what. Especially where mixed numbers are involved, parentheses help show that the number 3 1/3 is not supposed to be interpreted as the product of 3 and 1/3.

4 0
3 years ago
Apply Gaussian quadrature with n = 4 to approximate integrate sin x^2dx from 1 to 5
maks197457 [2]
First, recall that Gaussian quadrature is based around integrating a function over the interval [-1,1], so transform the function argument accordingly to change the integral over [1,5] to an equivalent one over [-1,1].

x=2t+3\iff t=\dfrac x2-\dfrac32\implies2\mathrm dt=\mathrm dx
x=1\implies t=\dfrac{2-6}4=-1
x=5\implies t=\dfrac{10-6}4=1

So,

\displaystyle\int_{x=1}^{x=5}\sin x^2\,\mathrm dx=\displaystyle2\int_{t=-1}^{t=1}\sin(2t+3)^2\,\mathrm dt

Let f(t)=2\sin(2t+3)^2. With n=4, we're looking for coefficients c_i and nodes x_i, with 1\le i\le4, such that

\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx c_1f(x_1)+\cdots+c_4f(x_4)

You can either try solving for each with the help of a calculator, or look up the values of the weights and nodes (they're extensively tabulated, and I'll include a link to one such reference).

Using the quadrature, we then have

\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx0.3749f(-0.8611)+0.6521f(-0.3400)+0.6521f(0.3400)+0.3749f-0.8611)
\displaystyle\int_{-1}^1f(t)\,\mathrm dt\approx0.5790
4 0
3 years ago
The total cost of a vacation to a rain forest includes a fee of $560 for the tour guide, plus $630 per person. The function y=56
slava [35]
Hello,

We have the function y=560+630/x 

We have x as 0 making y=630
4 0
3 years ago
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