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3 years ago

5

Vectors a and b have scalar product â6.00, and their vector product has magnitude +9.00. what is the angle between these two vec

tors?

1 answer:

salantis [7]3 years ago

3 0

Answer:

Value of angle between vector a and b is $56.30^{\circ}$ .

Explanation:

Vectors a and b have scalar product 6.00

Let $\theta$ be the angle between a and b.

$\vec{a}.\vec{b} = 6$

ab cos $\theta$ = 6 ...(1)

Vectors a and b have magnitude of vector product 9.00

$\vec{a} \times\vec{b} = 9$

ab sin $\theta$ = 9 ...(2)

Dividing equation (2) by (1) we get

$\frac{ab sin \theta}{ab cos \theta} = \frac{9}{6}$

tan $\theta$ = 1.5

$\theta = tan ^{-1} (1.5)$

$\theta$ = $56.30^{\circ}$

Thus, value of angle between vector a and b is $56.30^{\circ}$ .

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EleoNora [17]

Answer:

The tank is losing $4.976*10^{-4} m^3/s$

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Explanation:

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We are being informed that both the tank and the hole is being exposed to air :

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Also as the tank is voluminous ; we take the initial volume $v_1$ ≅ 0 ;

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$v_2 = \sqrt{[2*9.81*(5)]$

$v_2= 9.9 \ m/s$ as it leaves the hole at the base.

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J = πr² $v_2$

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b)

How fast is the water from the hole moving just as it reaches the ground?

In order to determine that; we use the relation of the velocity from the equation of motion which says:

v² = u² + 2gh ₂

v² = 9.9² + 2×9.81×15

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Amount of work done is zero and so power = 0 watts.

<u>Explanation:</u>

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Answer:

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