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4vir4ik [10]
3 years ago
14

Solve the system of equations 3y+2z=12 and y-z=9

Mathematics
1 answer:
muminat3 years ago
4 0
Mulitply second equation by 2 and add to first

3y+2z=12
<u>2y-2z=18 +</u>
5y+0z=30

5y=30
divide 5
y=6

sub back
y-z=9
6-z=9
minus 6
-z=3
times -1
z=--3

x=-3
y=6
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Mathematics Areas and perimeters ​
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Answer:

54.5 Sq. cm

Step-by-step explanation:

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(here, the base is 8 and height is 6)

= 1/ 2 × 6 × 8

= 4 × 6

<u>= 24 Sq. cm</u>

<em>area of a circle</em> = \pi r²

(r is the radius that is diameter/ 2, and the value of \pi is 3. 14)

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= 3. 14.× (5)²

= 3.14 × 25

<u>= 78.5 Sq. cm</u>

area of the shaded region = area of Circle - area of triangle

= 78.5 - 24

<h3>= 54.5 Sq. cm</h3>

that is option 3

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