Whole numbers are a subset of integers, which in turn are a subset of rational numbers.
So, every whole number is an integer, and every integer is a rational number.
So, it is possible for a rational number not to be an integer. Think of any decimal number: 1.356 is a rational number, but it's not an integer.
On the other hand, if a number is not an integer, it can't be a whole number, because all whole numbers are integers.
Answer:
z=-y-11
Step-by-step explanation:
let's take out the parenthesis
-z-11=y
Now put 11 on the other side
-z=y+11
Then make z positive
z=-y-11
Answer:
Step-by-step explanation:
<u>Given parallelogram JKLM with:</u>
<u>Find:</u>
<u>We know opposite angles of parallelogram are congruent:</u>
<u>Use angle addition postulate:</u>
- m∠KLM = m∠KLO + m∠MLO
- m∠KLM = 53° + 59°
- m∠KLM = 112°
Answer:
a2 – b2 = (a – b)(a + b)
(a + b)2 = a2 + 2ab + b2
a2 + b2 = (a + b)2 – 2ab
(a – b)2 = a2 – 2ab + b2
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
(a – b – c)2 = a2 + b2 + c2 – 2ab + 2bc – 2ca
(a + b)3 = a3 + 3a2b + 3ab2 + b3 ; (a + b)3 = a3 + b3 + 3ab(a + b)
(a – b)3 = a3 – 3a2b + 3ab2 – b3 = a3 – b3 – 3ab(a – b)
a3 – b3 = (a – b)(a2 + ab + b2)
a3 + b3 = (a + b)(a2 – ab + b2)
(a + b)4 = a4 + 4a3b + 6a2b2 + 4ab3 + b4
(a – b)4 = a4 – 4a3b + 6a2b2 – 4ab3 + b4
a4 – b4 = (a – b)(a + b)(a2 + b2)
a5 – b5 = (a – b)(a4 + a3b + a2b2 + ab3 + b4
Find the area of the circle using A=pi * r^2 and then divide that answer by 2 and that will get you the area of the semicircle.
