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crimeas [40]
4 years ago
9

Write a balanced equation for the combination of magnesium and oxygen to form magnesium oxide

Chemistry
2 answers:
Tamiku [17]4 years ago
7 0

Answer:

B

Explanation:

ElenaW [278]4 years ago
4 0

Answer:

The answer to your question is:   2Mg   +   O₂    ⇒   2MgO

Explanation:

Data

Magnesium = Mg

Oxygen = O

Equation

                       2Mg   +   O₂    ⇒   2MgO

                      Reactants                 Products

                          2   --------  Mg  ----------  2

                         2    --------   O    ---------   2

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In the lab, you added an excess of acetic acid to drive the reaction forward, favoring products at equilibrium according to Le C
AysviL [449]

Answer:

Remove exess water

Explanation:

The reaction involved is an esterification reaction. Esterification is a reaction in which alcohol and carboxylic acid reacts to yield an ester and water. It is analogous to the inorganic neutralization reaction.

According to Le Chatelier's principle , one method of driving the equilibrium towards the forward reaction is by removal of one of the products. In this case, if water is removed, the forward reaction is favoured.

6 0
4 years ago
Each step in the following process has a yield of 90.0 %. CH 4 + 4 Cl 2 ⟶ CCl 4 + 4 HCl CCl 4 + 2 HF ⟶ CCl 2 F 2 + 2 HCl The CCl
Rainbow [258]

Answer:

4.86 moles of HCl

Explanation:

1. First write the balanced chemical equations involved in the process:

CH_{4}+_4Cl_{2}=CCl_{4}+_4HCl

CCl_{4}+_2HF=CCl_{2}+F_{2}+_2HCl

2. Calculate what amount of CCl_{4} is formed in the first reaction.

3.00molesCH_{4}*\frac{1molCCl_{4}}{1molCH_{4}}=3.00molesCCl_{4}

As the yield of each reaction is 90.0%, the amount of CCl_{4} produced is the following:

3.00molesCCl_{4}*0.90=2.7molesCCl_{4}

3. Calculate the amount of HCl produced.

2.7molesCCl_{4}*\frac{2molHCl}{1molCCl_{4}}=5.4molesHCl

The total amount of HCl produced with a 90.0% yield is:

5.4molesHCl*0.90=4.86molesHCl

4 0
3 years ago
The graph below shows how the temperature and volume of a gas vary when the number of moles and the pressure of the gas are held
DedPeter [7]

Answer:

Option C. By increasing the temperature

Explanation:

From the graphical illustration above, we see clearly that the volume and temperature of the gas are directly proportional. This implies that as the temperature increases, the volume will also increase and as the temperature decreases, the volume will also decrease. This can further be explained by using the ideal gas equation as shown below:

PV = nRT

P is the pressure.

V is the volume.

n is the number of mole.

R is the gas constant.

T is the temperature.

PV = nRT

Divide both side by P

V = nRT/P

Since n and P are constant, the equation above becomes:

V & T

V = KT

K is the constant.

The above equation i.e V = KT implies that:

As T increases, V will also increase and as T decreases, V will also decrease.

Considering the question given above,

The volume of the gas can be increased if the temperature is increased.

6 0
4 years ago
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________ is a major dissolved volatile constituent in both magmas and volcanic gases?
Mnenie [13.5K]
water is a major dissolved volatile constituent in both magmas and volcanic gases
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