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3 years ago

Which factor below does not affect how fast a solute dissolves in a solvent?

2 answers:

3 0

Stirring this is because the three elements are factors affecting dissolving of a solvent. Eg temprature affects in hotness or coldness, Particle size affects whether it is big or small while quantity of soluble affects by the amount

son4ous [18]3 years ago

3 0

Answer: The answer is B. Particle size of the solvent

Explanation: Solvent is usually in a liquid state (or sometimes in gaseous or solid-state). It is used in dissolving solutes (which are usually in solid-state). Although, the solute can also be in the form of a liquid and gaseous state.

When a solute dissolves in a solvent, a solution is formed. An example is when you have a salt (solute) dissolved in water(solvent) it will form a saline solution( which of course is the solution).

Factors that determine the rate a solute dissolves in a solvent include; temperature, stirring, the particle size of solute, the quantity of solute.

Temperature affects the rate of dissolving because, in a warmer solvent, solute has more energy to move compared in a cool solvent.

Stirring helps in the distribution of a solute in a solvent. When u agitate or stir, the solute will dissolve faster in the solvent.

The particle size of solute affects the rate of dissolving because a smaller particle size of a solute will dissolve faster than a solute with larger particle size.

Quantity of solute can also be a factor because when you have different quantities of solutes in a particular quantity of the same solvent, the rate of dissolving will be different provided they undergo the same factors I.e the solute with higher quantity will dissolve slower compared to the solute with less quantity provided the solvent is in the same temperature state.

Since solvents are usually in a liquid state, the particle size of the solvents won't be a factor of the rate at which the solutes will dissolve.

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Mercury is the only metal that is a liquid at room temperature. When mercury vapor is inhaled, it is readily absorbed by the lun

Lapatulllka [165]

Answer:

P = 0.0166 mm Hg

Explanation:

To solve this question, we need to use the Clausius Clapeyron equation, which is a commonly used expression to calculate vapour pressure at a given temperature. We have the enthalpy of vaporization of the mercury, so, let's write the equation:

Clausius Clapeyron equation:

Ln (P₂ / P₁) = (-ΔHv / R)(1/T₂ - 1/T₁) (1)

Where:

R: universal constant of gases (8.314 J / K.mol)

P₂: Vapour pressure at 43°C (or 316 K)

P₁: Pressure of mercury at the boiling point (1 atm)

T₂: temperature at 43 °C

T₁: Boiling point of mercury (357 °C or 630 K)

As we are given the boiling point of the mercury, we can safely assume that the pressure at this point is 1 atm, becuase remember that when a sustance boils, is because it's internal pressure has reached the atmospherical pressure of 1 atm. With this clear, all we just need to do is solve for P₂. We are going to do this very slowly so you can understand the process. First let's replace the given data:

Ln (P₂ / 1) = (-59100 J/mol / 8.314 J / K.mol) (1/316 - 1/630)

Ln P₂ = -7108.49 * (3.16x10⁻³ - 1.59x10⁻³)

Ln P₂ = -7108.49 * (1.51x10⁻³)

Ln P₂ = -10.7338

P₂ = 10⁽⁻¹⁰°⁷³³⁸⁾

P₂ = 2.18x10⁻⁵ atm

We can express this value in mm Hg and it will be:

P₂ = 2.18x10⁻⁵ * 760

Hope this helps

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2 years ago

Build a prototype or test model of the invention

KIM [24]

What invention I want to help you but I am confused

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3 years ago

What is the mass of 1.25 mol of zinc

Ilya [14]

Answer:

1 mole is equal to 1 moles Zinc, or 65.38 grams.

Explanation:

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3 years ago

According to the following position vs. Time graph the bicyclist was

julia-pushkina [17]

Answer:

According to the following position vs. Time graph the bicyclist was : D

D. Not moving for the first two seconds, then begin moving at the constant speed.

Explanation:

$Speed = \frac{Distance}{time}$

Along Y-axis = Distance in meters

Along X-axis = Time taken in second

For first 2 seconds the The object has not changed its position.There is Zero distance covered.So , Speed = 0
After 2 second,The Object changed the distance by equal amount in equal interval of time.(Uniform Speed).Hence at each point after 2 second, there is same value speed