Question

Calculate the approximate radius of the 31P nucleus (assume r0 = 1.3x10-15 m).

Answer 1

Answer:

4.08 x 10⁻¹⁵ m

Explanation:

r₀ = constant of proportionality = 1.3 x 10⁻¹⁵ m

r = radius of the nucleus 31P = ?

A = mass number of the nucleus 31P = 31

Radius of the nucleus is given as

$r=r_{o}A^{\frac{1}{3}}$

Inserting the values

$r=(1.3\times 10^{-15})(31)^{\frac{1}{3}}$

$r=(1.3\times 10^{-15})(3.14)$

r = 4.08 x 10⁻¹⁵ m