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3 years ago

Calculate the approximate radius of the 31P nucleus (assume r0 = 1.3x10-15 m).

Physics

1 answer:

tekilochka [14]3 years ago

6 0

Answer:

4.08 x 10⁻¹⁵ m

Explanation:

r₀ = constant of proportionality = 1.3 x 10⁻¹⁵ m

r = radius of the nucleus 31P = ?

A = mass number of the nucleus 31P = 31

Radius of the nucleus is given as

$r=r_{o}A^{\frac{1}{3}}$

Inserting the values

$r=(1.3\times 10^{-15})(31)^{\frac{1}{3}}$

$r=(1.3\times 10^{-15})(3.14)$

r = 4.08 x 10⁻¹⁵ m

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Explanation:

Momentum

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