Answer:
the car accelerates in
Explanation:
here's the solution : -
we know,
=》
=》
=》
=》
so, acceleration = 1500 m/s^2
now,
=》
here, a = acceleration, v = final velocity,
u = initial velocity, t = time taken.
So,
=》
=》
=》
=》
Answer:
1. What was the diameter of the hailstone in inches_5.09_ and in cm___12.92___ and in feet ____0.42___?
2. What was the total volume of the hailstone in cubic inches___68.64___ and cubic feet____0.03____?
3. What was the fall velocity of this hailstone in m/s_____2.584____ and in mph___5.78_____?
Explanation:
1. If the circumference (L) of the stone is 16 inches, then from the following equation
1 inch = 2.54 cm = 0.08 ft, so 5.09 inches = 12..92 cm = 0.42 ft
2. The total volume is
3. The fall velocity is V = kd, where k = 20 if d is in cm. Let's calculate the fall velocity in cm.
2.584 m/s = 5.78 mph
First, let us derive our working equation. We all know that pressure is the force exerted on an area of space. In equation, that would be: P = F/A. From Newton's Law of Second Motion, force is equal to the product of mass and gravity: F = mg. So, we can substitute F to the first equation so that it becomes, P = mg/A. Now, pressure can also be determined as the force exerted by a fluid on an area. This fluid can be measure in terms of volume. Relating volume and mass, we use the parameter of density: ρ = m/V. Simplifying further in terms of height, Volume is the product of the cross-sectional area and the height. So, V = A*h. The working equation will then be derived to be:
P = ρgh
This type of pressure is called the hydrostatic pressure, the pressure exerted by the fluid over a known height. Next, we find the literature data of the density of seawater. From studies, seawater has a density ranging from 1,020 to 1,030 kg/m³. Let's just use 1,020 kg/m³. Substituting the values and making sure that the units are consistent:
P = (1,020 kg/m³)(9.81 m/s²)(11 km)*(1,000 m/1km)
P = 110,068,200 Pa or 110.07 MPa
