The duty of the AHJ is to: (C). review installation designs and determine if they fall under Code jurisdiction
<h3>Meaning of AHJ</h3>
AHJ can be defined as that means Authority Having Jurisdiction
AHJ can be defined as an organization, office, or individual that are responsible for the issuance of permits, enforcing the requirements of a code or standard and approving materials or a procedure.
In conclusion, The role of the AHJ are outlined in the paragraph above.
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Answer:
40 Hz
Explanation:
f = 1/T = 1 / 0.025 = 40 Hz
Answer:
18.89cm
Explanation:
As we know that the person is standing 5m in front of the camera

The focal length of the lens =50cm
f=50 cm
By Lens formula we have:

By the formula of magnification

The height of the image formed is 18.89cm.
Answer:
D
Explanation:
because it is the only one that has something to do with heat keyword would be boiling
Answer:

Explanation:
The attached figure shows the whole description. Considering the applied force is 100 N.
The acceleration of both blocks A and B, 
Firstly calculating the mass m using the second law of motion as :
F = ma
m is the mass


m = 125 kg
It suddenly encounters a surface that supplies 25.0 N a friction, F' = 25 N



So, the new acceleration of the block is
. Hence, this is the required solution.