Answer: 2.34s
Explanation:
Given the following :
Horizontal Velocity(V) = 3.22m/s
Horizontal Distance = 7.54m
Therefore, the time spent in the air can be calculated thus:
Using the relation:
Speed = distance / time
3.22m/s = 7.54m / time
Time = 7.54m / 3.22m/s
Time = 2.34s
Answer:
Explanation:
All existing matter and space considered as a whole; the cosmos. The universe is believed to be at least 10 billion light years in diameter and contains a vast number of galaxies; it has been expanding since its creation in the Big Bang about 13 billion years ago.
Answer:
The ram has done more work because the rate at which the ram work is 1.6m/s and Hari is 1.1m/s
Answer:
2) f = 0.707 Hz
Explanation:
Given m₁ = 1.0 kg , f₁ = 1.0 Hz
So using the equation
f₁ = ( 1 / 2 π ) * √K / m₁
Solve to determine K' constant of spring
K = m * ( 4 π ² * f ² )
K = 1.0 kg * ( 4 π ² 1.0² Hz )
K = 39.4784176
So given 2.0 kg the frequency can be find using formula
f₂ = ( 1 / 2 π ) * √K / m₂
f₂ = ( 1 / 2 π ) * √39.4784176 / 2.0 kg
f₂ = 0.707 Hz
Answer:
2.82 s
Explanation:
The ball will be subject to the acceleration of gravity which can be considered constant. Therefore we can use the equation for uniformly accelerated movement:
Y(t) = Y0 + Vy0 * t + 1/2 * a * t^2
Y0 is the starting position, 2.3 m in this case.
Vy0 is the starting speed, 13 m/s.
a will be the acceleration of gravity, -9.81 m/s^2, negative because it points down.
Y(t) = 2.3 + 13 * t - 1/2 * 9.81 * t^2
It will reach the ground when Y(t) = 0
0 = 2.3 + 13 * t - 1/2 * 9.81 * t^2
-4.9 * t^2 + 13 * t + 2.3 = 0
Solving this equation electronically gives two results:
t1 = 2.82 s
t2 = -0.17 s
We disregard the negative solution. The ball spends 2.82 seconds in the air.
