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DiKsa [7]
3 years ago
11

Mr. Fitch hires a landscape architect to renovate his front yard the rectangular yard is 30 feet long is the area of the front y

ard is 600 ft.² determine the week of the yard
Mathematics
1 answer:
Vinil7 [7]3 years ago
7 0

Answer:

The width of the yard is 20 ft

Step-by-step explanation:

In this particular question, we are asked to calculate the width of the rectangular front yard given the area of the front yard and the length of the front yard.

Mathematically, the area of the front yard is calculated by multiplying the length of the front yard by the breadth of the front yard.

Let’s say A = L * W

Substituting the known values, the unknown width would thus be:

W = A/L = 600 sq.ft / 30ft

W = 20 ft

You might be interested in
A farmer has 96 apples to sell at the farmers market. She wants to bag the apples before going. How many ways can the farmer bag
Tcecarenko [31]

Answer and explanation:

Farmer's number of apples = 96 apples

Given that Farmer needs to bag the apples so that there are at least 4 apples in each bag(not less than 4 apples in each bag) and not more than 10 apples in each bag

And also all apples in each bag are equal

We need to find the numbers between 4 and 10(including 4 and 10) that can divide 96 without a remainder

4 can divide 96= 24

5 cannot divide 96 without remainder

6 can divide 96 =16

7 cannot divide 96 without remainder

8 can divide 96=12

9 cannot divide 96 without remainder

10 cannot divide 96 without remainder

From the above we see that the factors of 96 = 4, 6, 8 between 4 and 10

4 apples = 24 bags

6 apples = 16 bags

8 apples = 12 bags

Therefore, there can be 3 possible ways of having equal number of apples in each bag between 4 and 10 apples

8 0
2 years ago
For the polynomial function ƒ(x) = −x6 + 3x4 + 4x2, find the zeros. Then determine the multiplicity at each zero and state wheth
murzikaleks [220]

There is a multiple zero at 0 (which means that it touches there), and there are single zeros at -2 and 2 (which means that they cross). There is also 2 imaginary zeros at i and -i.


You can find this by factoring. Start by pulling out the greatest common factor, which in this case is -x^2.


-x^6 + 3x^4 + 4x^2

-x^2(x^4 - 3x^2 - 4)


Now we can factor the inside of the parenthesis. You do this by finding factors of the last number that add up to the middle number.


-x^2(x^4 - 3x^2 - 4)

-x^2(x^2 - 4)(x^2 + 1)


Now we can use the factors of two perfect squares rule to factor the middle parenthesis.


-x^2(x^2 - 4)(x^2 + 1)

-x^2(x - 2)(x + 2)(x^2 + 1)


We would also want to split the term in the front.


-x^2(x - 2)(x + 2)(x^2 + 1)

(x)(-x)(x - 2)(x + 2)(x^2 + 1)


Now we would set each portion equal to 0 and solve.


First root

x = 0 ---> no work needed


Second root

-x = 0 ---> divide by -1

x = 0


Third root

x - 2 = 0

x = 2


Forth root

x + 2 = 0

x = -2


Fifth and Sixth roots

x^2 + 1 = 0

x^2 = -1

x = +/- \sqrt{-1}

x = +/- i

7 0
3 years ago
Omg pls help me i only have a few min left imma cry
hodyreva [135]

Answer:

option B

Step-by-step explanation:

since DA and CB are equal and originate from same line segmnet, they are parallel, so angle D and angle C are equal, angle A and anfle B are equal and angle E is the same for both,

4 0
3 years ago
Yes or no awnser pls
kifflom [539]

Answer:

No the question iant a function

5 0
2 years ago
WHO CAN solve it Please !
Mariulka [41]

Answer:

a) True

<em>      </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha =0<em></em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given that the definite integration</em>

<em>            </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha<em></em>

<em>we know that the trigonometric formula</em>

<em> sin²∝+cos²∝ = 1</em>

<em>            cos²∝ = 1-sin²∝</em>

<u><em>step(ii):-</em></u>

<em>Now the  integration</em>

<em>         </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha<em></em>

<em>                                      = </em>\int\limits^\pi _0 {cos\alpha } \, dx<em></em>

<em>Now, Integrating </em>

<em>                                  </em>= ( sin\alpha )_{0} ^{\pi }<em></em>

<em>                                = sin π - sin 0</em>

<em>                               = 0-0</em>

<em>                              = 0</em>

<u><em>Final answer:-</em></u>

<em>      </em>\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha  }   )d\alpha =0<em></em>

<em></em>

<em></em>

5 0
3 years ago
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