Step-by-step explanation:
y=kxz
13=k x 5 x 8
13= 40k
K=13/40
a. y=13/40 x 4 x 10
y=13/40 x 40
y=13
b. 20=13/40 x x x 12
20=13/40 x 12x
20=<u>156x</u>
40
20 x 40=156x
800=156x
X=<u>800</u>
156
X=<u>200</u>
39
X=5 5/39
C. 15=13/40 x 6 x z
15=<u>78z</u>
40
15x40=78z
600=78z
Z=<u>600</u>
78
Z=<u>100</u>
3
Z=7 9/13
Answer:
x = 3, y = -8
x = 4, y = -5
x = 5, y = -2
x = 6, y = 1
Step-by-step explanation:
You can apply the equation y = 3x - 17 for the different values for x.
x = 3
y = 3(3) - 17
= 9 - 17
= -8
x = 4
y = 3(4) - 17
= 12 - 17
= -5
x = 5
y = 3(5) - 17
= 15 - 17
= -2
x = 6
y = 3(6) - 17
= 18 - 17
= 1
Answer:
the answer will be y=2x
Step-by-step explanation:
Answer:
$2600 was invested on the 1% account while $2400 was invested on the 6% account.
Step-by-step explanation:
For simple interest we must apply the following formula:
M = C*r*t
Where M is the amount of interest generated, C is the invested money, r is the rate of interest and t is the elapsed time.
The sum of capital investead in each account, "x" for the 1% interest one and "y" for the 6% interest one, must be equal to the original $5000. The same way as the interest generated from these investments must be equal to the earnt $170. So we have:
x + y = 5000
For the first account:
M1 = x*0.01*1 = 0.01*x
For the second account:
M2 = y*0.06*1 = 0.06*y
The sum of interests:
0.01*x + 0.06*y = 170
We have a system of equations as shown below:
x + y = 5000
0.01*x + 0.06*y = 170
Multiplying the first equation by -0.01 and adding both equations we have:
-0.01*x - 0.01*y = -50
0.01*x + 0.06*y = 170
0.05*y = 120
y = 120 / 0.05 = $2400
x = 5000 - 2400 = $2600
$2600 was invested on the 1% account while $2400 was invested on the 6% account.
