A. [1,2] sigmatropic hydrogen migration
Answer:
The percent ionization is 0,16%
Explanation:
The percent ionization is defined as the number of ions that exist in a substance.
![PI=\frac{[A-]}{[HA]} x100](https://tex.z-dn.net/?f=PI%3D%5Cfrac%7B%5BA-%5D%7D%7B%5BHA%5D%7D%20x100)
First, we find the [A-] using the ka equation
HA ⇄ 
[H+] = [A-]
![Ka=\frac{[H+][A-]}{[HA]}\\ \\](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%2B%5D%5BA-%5D%7D%7B%5BHA%5D%7D%5C%5C%20%5C%5C)
since the ionization constant is very small we can assume that the final concentration of [HA] is the same
![Ka=\frac{[H+]^{2} }{[HA]} \\\\](https://tex.z-dn.net/?f=Ka%3D%5Cfrac%7B%5BH%2B%5D%5E%7B2%7D%20%7D%7B%5BHA%5D%7D%20%5C%5C%5C%5C)
![[H+]=\sqrt[2]{Ka.[HA]} \\\\](https://tex.z-dn.net/?f=%5BH%2B%5D%3D%5Csqrt%5B2%5D%7BKa.%5BHA%5D%7D%20%5C%5C%5C%5C)
![[H+] =\sqrt{(2,610^{-7} )(0,1)} = 1,61210^{-4}](https://tex.z-dn.net/?f=%5BH%2B%5D%20%3D%5Csqrt%7B%282%2C610%5E%7B-7%7D%20%29%280%2C1%29%7D%20%20%3D%201%2C61210%5E%7B-4%7D)
Now we calculate the percent ionization using these values

PI=0,16%
Answer : The products of the chemical reaction are,
and 
Explanation :
Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.
When sodium bromide react with silver nitrate then it react to give sodium nitrate and silver bromide as a product.
The balanced chemical reaction will be:

The given reaction is a double-displacement reaction in which the cation of two reactants molecule exchange their places to give two different products.
The species present on the left side of the right arrow is the reactant and the species present on the right side of the right arrow is the product.
In the balanced chemical reaction,
and
are reactants.
and
are products.
Hence, the products of the chemical reaction are,
and 
Answer:
4.9 atm
Explanation:
convert 16.0g of CH4 to moles
16.0 g CH4 x 1 mol CH4/16.0 g CH4 = 1.00 mol of methane
convert the temp into Kelvins: 27 + 273 = 300.K
PV = nRT
(P) (5.0 L) = (1.00 mol) (0.0821 L atm/mol K) (300.K)
P = 4.9 atm