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drek231 [11]
3 years ago
11

How many moles of Na2CO3 are in 100.0ml of a 2.0M solution?

Chemistry
1 answer:
Anna [14]3 years ago
6 0

M = moles of solute / liters of solution

2.00 M = x / 10.0 L

x = 20.0 mol

Suppose the molarity was listed as 2.0 M (two sig figs). How to display the answer? Like this:

20. mol

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Kekshebeeosnebwjelrldksbsb
Grace [21]
Hey
Explanation:
The answer is this because
7 0
3 years ago
Read 2 more answers
How many moles are contained in 3.131 × 1024 particles?
AleksAgata [21]

<u>Given:</u>

The number of particles = 3.131 * 10²⁴

<u>To determine:</u>

The number of moles corresponding to the given particles

<u>Explanation:</u>

1 mole corresponds to Avogadro's number of particles = 6.023 * 10²³ particles

Therefore, the given particles would correspond to:

3.131* 10²⁴ particles * 1 moles/6.023 * 10²³ particles = 5.199 moles

Ans: A) 5.199 moles are contained in 3.131* 10²⁴ particles



3 0
3 years ago
Read 2 more answers
Which element forms an ionic compound when it reacts with lithium?
creativ13 [48]
<h3>Answer:</h3>

              Br (Bromine)

<h3>Explanation:</h3>

Li and K,

As the electronegativity difference between Li and K is less than 1.7 therefore, ionic bond cannot form between these two metals.

Li and Fe,

The electronegativity difference is less than 1.7 so neither electron loss nor electron gaining will take place between these two metals. Therefore, there will be no ionic bond between them.

Li and Kr,

As Krypton is a noble gas and does not react due to complete octet hence the formation of KrLi is difficult. However, Krypton can make compounds like KrF₂ e.t.c. Therefore we can skip this option.

For Li and K,

                   E.N of Bromine             =   2.96

                   E.N of Lithium               =   0.98

                                                             ________

                   E.N Difference                     1.98          (Ionic)

This ionic compound is possible and is the correct option because ionic compounds are always made by metals and non metals and here the combination is perfect.

<h3>Conclusion:</h3>

                          Lithium (a metal) and form Ionic bond with Bromine (a non metal)

4 0
3 years ago
Read 2 more answers
How many moles of pcl5 can be produced from 23.0 g of p4 (and excess cl2)?
Masja [62]
The balanced equation for the above reaction is as follows
P4 + 10Cl2 —> 4PCl5
P4 is the limiting reactant. Stoichiometry of P4 to PCl5 is 1:4
The mass of P4 reacted = 23.0 g
Number of P4 moles = 23.0 g/ 124 g/mol = 0.185 mol
According to the stoichiometry the number of PCl5 moles produced are 4 times the amount of P4 moles reacted
Therefore PCl5 moles = 0.185 x 4 = 0.74 mol
3 0
3 years ago
This is for chemistry<br> I need help for this question
solong [7]

Answer:

what is the quetion.......

Explanation:

7 0
3 years ago
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