how does what show? i mean an object at rest will never move unless you put some kind of force on it weather that the force of gravity or force from your hand but i cannot answer this question unless you give some kind of picture or something
The radius of the given circular path moved by the proton which is perpendicular to a magnetic field of 0.87 T determined as 4 cm.
<h3>
Magnetic force of the proton</h3>
The magnitude of the magnetic force on the proton is determined using the following formula;
F = qvBsin(θ)
<h3>Centripetal force on the proton</h3>
The centripetal force of the circular path is given as;
F = mv²/r
Solve the two equations together,
Where;
- v is the speed of the proton
<h3>Speed of the proton</h3>
The speed of the proton is determined from its kinetic energy;
<h3>Radius of the circular path</h3>
The radius of the circular path is calculated as follows;
Learn more about magnetic force here: brainly.com/question/13277365
Answer:
The magnitude of the force each cousin exerts on the dinghy is 183.6 N and 78.4 N.
Explanation:
When the cousins pull in the same direction we have:
(1)
Where:
F₁ and F₂ are the forces exerted by the two boys.
m: is the mass of the dinghy = 200 kg
: is the acceleration in the east direction
When the cousins pull in opposite directions we have:
(2)
By adding equation (1) and (2):
Now, by entering F₁ into equation (1) we can find F₂:
Therefore, the magnitude of the force each cousin exerts on the dinghy is 183.6 N and 78.4 N.
I hope it helps you!