Answer:
Displacement of Mr. Llama: Option D. 0 miles.
Explanation:
The magnitude of the displacement of an object is equal to the distance between its final position and its initial position. In other words, as long as the initial and final positions of the object stay unchanged, the path that this object took will not affect its displacement.
For Mr. Llama:
- Final position: Mr. Llama's house;
- Initial position: Mr. Llama's house.
The distance between the final and initial position of Mr. Llama is equal to zero. As a result, the magnitude of Mr. Llama's displacement in the entire process will also be equal to zero.
Answer:
a) increase
Explanation:
The frequency of sound produced due to vibration of a string is governed by the following formula
n = 1/2L√T/m ;
L is length of the string in vibration, T is tension in the string and m is mass of string per unit length.
So frequency is inversely proportional to length of the string. Hence shortning of length of string increases the frequency of vibration.
Answer:
geotric earth simulator I think ya I have no idea
Answer:
4.14 m
Explanation:
In the last leg of the journey the ball covers 2 m in 2ms or 0.2 s .
Let in this last leg , u be the initial velocity.
s = ut + 1/2 g t²
2 = .2 u + .5 x 9.8 x .04
u = 9.02 m /s .
Let v be the final velocity in this leg
v² = u² + 2 g s
v² = (9.02)² + 2 x 9.8 x 2
= 81.36 +39.2
v = 10.97 m / s
Now consider the whole height from where the ball dropped . Let it be h.
Initial velocity u = 0
v² = u² +2gh
(10.97 )² = 2 x 9.8 h
h = 6.14 m
Height from window
= 6.14 - 2m
= 4.14 m
Compressional waves are mechanical.mechanical waves require a medium to travel. in a vacuum, there is no matter, so the waves cannot travel
