Question

A gas evolved during the fermentation of sugar was collected. After purification its volume was found to be 25.0 l at 22.5°c and 702 mmhg. How many moles of gas were collected?

Answer 1

Answer:

Moles of gas collected = 0.952 mole

Explanation:

To calculate the number of moles of the gas collected, we use the equation given by ideal gas which follows:

$PV=nRT$

where,

P = pressure of the gas = 702 mmHg  

V = Volume of the gas = 25.0 L

T = Temperature of the gas = $22.5^oC=[22.5+273.15]K=295.65\ K$

R = Gas constant = $62.3637\text{ L.mmHg }mol^{-1}K^{-1}$

n = number of moles of gas = ?

Putting values in above equation, we get:

$702\ mmHg\times 25.0\ L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 295.65\ K\\\\n=\frac{702\times 25}{62.3637\times 295.65}\ mol=0.952mol$

Moles of gas collected = 0.952 mole