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Inga [223]
3 years ago
12

A gas evolved during the fermentation of sugar was collected. After purification its volume was found to be 25.0 l at 22.5°c and

702 mmhg. How many moles of gas were collected?
Chemistry
1 answer:
Ludmilka [50]3 years ago
5 0

Answer:

Moles of gas collected = 0.952 mole

Explanation:

To calculate the number of moles of the gas collected, we use the equation given by ideal gas which follows:

PV=nRT

where,

P = pressure of the gas = 702 mmHg  

V = Volume of the gas = 25.0 L

T = Temperature of the gas = 22.5^oC=[22.5+273.15]K=295.65\ K

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

n = number of moles of gas = ?

Putting values in above equation, we get:

702\ mmHg\times 25.0\ L=n\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 295.65\ K\\\\n=\frac{702\times 25}{62.3637\times 295.65}\ mol=0.952mol

<u>Moles of gas collected = 0.952 mole</u>

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