Answer:
4.7 g
Explanation:
The reaction that takes place is:
- 3CaCl₂(aq) + 2Na₃PO₄(aq) → Ca₃(PO₄)₂(s) + 6NaCl(aq)
First we <u>convert 4.8 g of CaCl₂ into moles</u>, using its <em>molar mass:</em>
- 4.8 g ÷ 110.98 g/mol = 0.0432 mol CaCl₂
Then we<u> convert CaCl₂ moles into Na₃PO₄ moles</u>, using the <em>stochiometric coefficients of the balanced reaction</em>:
- 0.0432 mol CaCl₂ *
= 0.0288 mol Na₃PO₄
Finally we <u>convert 0.0288 moles of Na₃PO₄ into grams</u>, using it<em>s molar mass</em>:
- 0.0288 mol Na₃PO₄ * 164 g/mol = 4.7 g