Here we have to explain and predict the product of the reaction between hept-3-yne and bromine (Br₂)
The reaction between hept-3-yne and bromine produces <em>trans</em>-3,4-dibromo-3-heptene.
The reaction between the unsaturated hydrocarbon with halogen remove the unsaturation in the molecule and produces di halo compound. The reaction proceed through the formation of bromonium ion.
In this reaction as the unsaturation present in the middle of the alkyl chain i.e. hept-3-yne. The reaction will stop after the formation of di-halo compound with one double bond as shown in the figure.
The product will be exclusively trans product as the bromine is a bulky group and the formation of bromonium ion (intermediate) will be one side of the unsaturated compound.
Answer:
1. 2+ (
).
2. 0 (
).
Explanation:
Hello,
In this case, the described chemical reaction is a redox reaction in fact, since the oxidation states of both magnesium and copper change as shown due to the displacement:

Therefore:
1. Since copper is the cation in the copper (II) nitrate, the (II) means that its charge is 2+ (
).
2. Since copper is alone, it means no electrons are being neither shared not given, its charge is 0 (
).
Best regards.
Answer: B) calcium nitrate
A I’m sure of it because it only makes since one would think ✊