Time Conversion C++: Given a time in -hour AM/PM format, convert it to military (24-hour) time.
1 answer:
Answer:
Code in C++::
#include<bits/stdc++.h>
#include<iostream>
#include<string>
#include<sstream>
using namespace std;
string timeConversion(string s){
/**
* Following two strings are declared named d and c respectively.
* String c will be storing the converted format time and we will return
* c as the answer.
*/
string d,c="";
/**
* String d stores "PM" or "AM"
*/
d=s.substr(8,2);
/**
* An integer named hr is declared below and it stores
* the hh part of string hh:mm:ssPM in integer format.
*/
int hr=atoi(s.substr(0,2).c_str());
if(hr==12 && d=="AM"){
/**
* Now suppose hr is 12 and its AM then we know that it's
* midnight and so hr must be 0.
*/
hr=0;
}
if(d=="PM" && hr!=12){
/**
* Suppose d is "PM" and hr is not 12 then we add 12 into hr.
*/
hr+=12;
}
if(hr<10){
/**
* Now suppose hr is less then 10 then we know that in final answer
* if hr is 7 then we need "07".
* So if hr < 10 then we add extra 0 at start of c string.
*/
c+="0";
}
/**
* Now we convert hr back to string using stringstream.
* A variable named hour is declared and we convert hr to string as follows.
*/
stringstream hour;
hour<<hr;
/**
* Finally we update the c string as required and return it at the end.
*/
c=c+hour.str()+s.substr(2,6);
return c;
}
int main(){
/**
* A string named s is declared and using cin we scan the string.
*/
string s;
cin>>s;
/**
* Below we call the function and pass string s as parameter.
* Whatever function returns, it is printed.
*/
cout<<timeConversion(s)<<endl;
return 0;
}
Explanation:
see thees attached
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