Question

Time Conversion C++: Given a time in -hour AM/PM format, convert it to military (24-hour) time.

Answer 1

Answer:

Code in C++::

#include<bits/stdc++.h>

#include<iostream>

#include<string>

#include<sstream>

using namespace std;

string timeConversion(string s){

/**

* Following two strings are declared named d and c respectively.

* String c will be storing the converted format time and we will return

* c as the answer.

*/

string d,c="";

/**

* String d stores "PM" or "AM"

*/

d=s.substr(8,2);

/**

* An integer named hr is declared below and it stores

* the hh part of string hh:mm:ssPM in integer format.

*/

int hr=atoi(s.substr(0,2).c_str());

if(hr==12 && d=="AM"){

/**

* Now suppose hr is 12 and its AM then we know that it's

* midnight and so hr must be 0.

*/

hr=0;

}

if(d=="PM" && hr!=12){

/**

* Suppose d is "PM" and hr is not 12 then we add 12 into hr.

*/

hr+=12;

}

if(hr<10){

/**

* Now suppose hr is less then 10 then we know that in final answer

* if hr is 7 then we need "07".

* So if hr < 10 then we add extra 0 at start of c string.

*/

c+="0";

}

/**

* Now we convert hr back to string using stringstream.

* A variable named hour is declared and we convert hr to string as follows.

*/

stringstream hour;

hour<<hr;

/**

* Finally we update the c string as required and return it at the end.

*/

c=c+hour.str()+s.substr(2,6);

return c;

}

int main(){

/**

* A string named s is declared and using cin we scan the string.

*/

string s;

cin>>s;

/**

* Below we call the function and pass string s as parameter.

* Whatever function returns, it is printed.

*/

cout<<timeConversion(s)<<endl;

return 0;

}

Explanation:

see thees attached