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timofeeve [1]
3 years ago
5

Approximately what percent of the Visible illuminated moons surface is seen in this phase

Physics
1 answer:
Firlakuza [10]3 years ago
8 0

well i see 25 % but half of the visable surface is illuminated

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The current in a hair dryer measures 15 amps the resistance of the hair dryer is 8 ohms
suter [353]

The <u><em>voltage</em></u> at the input to the hair dryer is

V = (current) · (resistance)

V = (15 A) · (8 Ω)

<em>V = 120 volts</em>

<em>__________________________________</em>

The <em><u>power</u></em> dissipated by the hair dryer is

P = (current)²· (resistance)

P = (15 A)² · (8 Ω)

<em>P = 1800 watts </em>

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3 years ago
In a double-slit experiment, it is observed that the distance between adjacent maxima on a remote screen is 1.0 cm. What happens
kobusy [5.1K]

Answer:

C) It increases to 2.0 cm

Explanation:

In a double-slit diffraction experiment, the distance on the screen between two adjacent maxima is given by

\Delta y = \frac{\lambda D}{d}

where

\lambda is the wavelength of the wave

D is the distance of the screen from the slits

d is the separation between the slits

In this problem, the initial distance between adjacent maxima is 1.0 cm. Later, the slit separation is cut in a half, which means that the new slit separation is

d'=\frac{d}{2}

Substituting into the equation, we find that the new separation between the maxima is

\Delta y' = \frac{\lambda D}{d/2}=2(\frac{\lambda D}{d})=2\Delta y

So, the distance increases by a factor 2: therefore, the new separation between the maxima will be 2.0 cm.

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3 years ago
Is thorium (the element) abundant?
laila [671]
The abundance of Thorium is more than that of uranium, in nature of course.
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3 years ago
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) a stone is dropped from the top of a cliff. It is seen to hit the ground below after 3.55 s. How high is the cliff?
Agata [3.3K]

We use kinematic equation of motion,

S =ut+ \frac{1}{2} gt^2

Here, s is distance traveled, u is the initial velocity, t is time taken and g is acceleration due to gravity.

Given, t =3.55 s.

We take,  u = 0 because stone has no initial velocity.

Therefore,

S = 0 \times t + \frac{1}{2} \times 9.8 \ m/s^2 \times (3.55)^2 s = 61.75 \ m

Thus,  the height of cliff is approximately 61.75 m.


5 0
4 years ago
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