Answer:
a 15.22 m/s
b 45.65 m
Explanation:
Using the same formula,
x = vt, where
x is now 45.65, and
t is 3 s, then
45.65 = 3v
v = 45.65/3
v = 15.22 m/s
See the attachment for the part b. We used the distance gotten in part B, to find question A
For this problem to be solved, we make use of the de Broglie formula which is written below as follows:
λ = h/mv
where h is 6.626×10⁻³⁴ J·s
9.74 × 10⁻³⁵ m = 6.626×10⁻³⁴ J·s/ (m)(46.9 m/s)
Solving for m,
<em>m = 0.145kg</em>
Answer:
c, 280,000J
Explanation:
You should use the equation KE (Kinetic Energy) = 
m = 2500
v = 15
KE = 
KE = 281250 Joules.
This is consistent with the answer B, as all of the parameters given to you are rounded to 2 significant figures so naturally, the answer should also be rounded to 2 sig figs.
KE = 280,000 J
Answer:
1)When a bullet is fired from the gun with a certain force (action) as a reaction an equal and opposite force is exerted on the gun. 2)when you jump, your legs apply a force to the ground, and the ground applies and equal and opposite reaction force that propels you into the air.