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Leona [35]
3 years ago
9

GRADE 9 SCIENCE I GRADE 9 SCIENCE 1 1 OF 24

Physics
1 answer:
andreyandreev [35.5K]3 years ago
7 0

Answer:

burger and cheese with applesauce

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Describe the results of Ernest Rutherford's gold-foil experiment and explain how his results changed ideas about the distributio
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In Rutherford's gold foil experiment, some of the positive particles would pass through the foil and some would bounce off. This led to a new theory that all of the positive subatomic particles were in the center of the atom instead of evenly spread throughout.
4 0
3 years ago
A bat strikes a 0.145-kg baseball. Just before impact, the ball is traveling horizontally to the right at 60.0 m/s , and it leav
nata0808 [166]

Answer:

F = -307.4 N

Explanation:

It is given that,

Mass of the baseball, m = 0.145 kg

Initial speed of the baseball, u = 60 m/s

Final speed of the baseball, v=65\ cos(30)=56.29\ m/s

Time of contact, t=1.75\ ms=1.75\times 10^{-3}\ s

(a) It is assumed to find the horizontal component of average force. It is given by :

F=m\dfrac{v-u}{t}

F=0.145\dfrac{56.29-60}{1.75\times 10^{-3}}

F = -307.4 N

So, the horizontal component of average force is 307.4 N. Hence, this is the required solution.

8 0
3 years ago
A heat engine has a maximum possible efficiency of 0.780. If it operates between a deep lake with a constant temperature of-24.8
Volgvan

Answer : The temperature of the hot reservoir (in Kelvins) is 1128.18 K

Explanation :

Efficiency of carnot heat engine : It is the ratio of work done by the system to the system to the amount of heat transferred to the system at the higher temperature.

Formula used for efficiency of the heat engine.

\eta =1-\frac{T_c}{T_h}

where,

\eta = efficiency = 0.780

T_h = Temperature of hot reservoir = ?

T_c = Temperature of cold reservoir = -24.8^oC=273+(-24.8)=248.2K

Now put all the given values in the above expression, we get:

\eta =1-\frac{T_c}{T_h}

0.780=1-\frac{248.2K}{T_h}

T_h=1128.18K

Therefore, the temperature of the hot reservoir (in Kelvins) is 1128.18 K

8 0
3 years ago
A soccer player kicks a 0.44 kg ball with a force of 57.6 N, what is the ball’s acceleration
noname [10]

THE BALL'S ACCELERATION IS 130.90\frac{m}{s}

Explanation:

According to Newton's second law "the force (F) acting on an object is equal to the mass (m) of an object times its acceleration (a)", meaning that when the soccer player kicks a ball, a force is acting on the ball, therefore increasing it's acceleration

SO FOR CALCULATING THIS WE WILL USE NEWTON LAW,

   FORCE = MASS × ACCELERATION

WE ARE GIVEN

FORCE = 57.6N

MASS= .44KG

SO HERE WE APPLYING FORMULA ,WE WILL GET

ACCELERATION = \frac{FORCE}{MASS}

ACCELERATION = \frac{57.6N}{.44KG}

ACCELERATION =130.90\frac{m}{s}

8 0
3 years ago
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