You are given the mass of the book with an initial
height of 0.77m. You are also given the final height of the book, 2m above the
floor. The problem requires you to find the work done on the book. It is said
that work is equal to force times distance. And that force is equal to mass
times acceleration due to gravity.
W=Fd
W=mgd=mgh
W=(1.7kg)(9.8m/s^2)(2m-0.77m)
W=20.49J
<span>The work is equal to 20.49J.</span>
Answer:
anything that contains atoms is the correct answer of given statement
Answer:
1027 N/C
3.42 x 10⁻⁶ T
Explanation:
I = Intensity of electromagnetic field = 1400 W/m²
E₀ = Maximum value of electric field
Intensity of electromagnetic field is given as
I = (0.5) ε₀ E₀² c
1400 = (0.5) (8.85 x 10⁻¹²) (3 x 10⁸) E₀²
E₀ = 1027 N/C
B₀ = maximum value of magnetic field
using the equation
E₀ = B₀ c
1027 = B₀ (3 x 10⁸)
B₀ = 3.42 x 10⁻⁶ T
We calculate the difference between the two velocities,
135 km/h - 35 km/h = 100 km/h
Then, convert the difference into units of m/s
100 km/h x (1000 m/ 1 km) x (1 hour / 3600 s) = 27.78 m/s
Then divide the difference by time.
acceleration = 27.78 m/s / 10.5 s = 2.65 m/s²
(2) In terms of g,
x = 2.65 / 9.80 = 0.27
Therefore, the answer would be,
a = 0.27g