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ohaa [14]
3 years ago
5

How does technology or research of a nuclear physicist involve electromagnetic or sound waves

Physics
1 answer:
kap26 [50]3 years ago
4 0

Answer: While quantum physics is usually concerned with the basic building blocks of light and matter, for some time scientists have now been trying to investigate the quantum properties of larger objects, thereby probing the boundary between the quantum world and everyday life. For this purpose, particles are slowed down with the help of electromagnetic waves and the motional energy is drastically reduced. Therefore, one also speaks of "motional cooling."

Quantum properties occur when particles are cooled to their fundamental quantum ground state, that is to the lowest possible energy level. While so far the only way to cool particles to the ground state has been to make them interact with photons trapped in an electromagnetic resonator, theoretical physicists led by Carlos Gonzalez-Ballestero and Oriol Romero-Isart from the Department of Theoretical Physics at the University of Innsbruck and the Institute of Quantum Optics and Quantum Information (IQOQI) of the Austrian Academy of Sciences in collaboration with experimentalist Jan Gieseler from Harvard University and ICFO in Barcelona now propose to make the motion of magnetic particles interact with the internal acoustic waves that are confined inside every particle.

Explanation:

Sound waves in micro-magnets

In analogy to photons -- the quanta of light -- vibrations in a solid body can be described as so-called phonons. These small sound wave packets propagate through the crystal lattice of the solid. "The phonons are very isolated and interact with the movement of the particle motion only through magnetic waves," explains Carlos Gonzalez-Ballestero. "In our work we now show that this interaction can be controlled by a magnetic field." This allows to realize quantum experiments without photons, and therefore even with light-absorbing particles. "Conversely, we also show that the strong interaction between motion and phonons provides a path to probe and manipulate the elusive and exotic dynamics of acoustic and magnetic waves in very small particles," adds Oriol Romero-Isart. The new method also opens up new possibilities for quantum information processing, for example, by using phonons as a quantum memory.

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The average radius of Mars is 3,397 km. If Mars completes one rotation in 24.6 hours, what is the tangential speed of objects on
choli [55]

Answer:

25 times the average speed

7 1
3 years ago
Read 2 more answers
A 60-kg woman stands on the very end of a uniform board, which is supported one-quarter of the way from one end and is balanced.
Tasya [4]

B 30 kg because


One quarter =1/2
Kg=60

1/2 of Kg
1/2*60
30 kg
5 0
3 years ago
A point charge is placed 3m from a 4uc charge what is the strength of the electric field on the point charge at this distance ro
Vlada [557]

The strength of the electric field on the point charge at this distance will be 4000 V/m.

<h3>What is the strength of the electric field?</h3>

The strength of the electric field is the ratio of electric force per unit charge.

The given data in the problem is;

Qis the unit charge = 4.0 × 10⁻⁶ C

E is the strength of the electric field

R is the distance from point charge = 3 m

The strength of the electric field is;

\rm E = \frac{KQ}{R^2} \\\\ \rm E = \frac{9 \times 10^9 \times 4 \times 10^{-6} \ C}{3^2} \\\\ E= 4000 V/m

Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.

To learn more about the strength of the electric field refer to the link;

brainly.com/question/15170044

#SPJ1

7 0
2 years ago
A twin-sized air mattress used for camping has dimensions of 75 cm by 225 cm by 17.5 cm when blown up. The weight of the mattres
konstantin123 [22]

Answer:

2870 N

Explanation:

There are three forces on the mattress.  Weight of the mattress, weight of the person, and buoyancy.

∑F = ma

B - mg - Mg = 0

Buoyancy is equal to the weight of the displaced fluid.

ρVg - mg - Mg = 0

ρV - m = M

Plugging in values:

M = (1000 kg/m³) (0.75 m × 2.25 m × 0.175 m) - 2 kg

M = 293 kg

The person's weight is therefore:

Mg = 293 kg × 9.8 m/s²

Mg = 2870 N

6 0
4 years ago
An object is observed for a time interval of 20 seconds. From time 6.7 s the object experiences a Force of 106 N that lasts unti
shusha [124]

Answer:

1654 kg m/s

Explanation:

The impulse experienced by an object is equal to the product between the force exerted on the object and the time during which the force lasts:

I=F\Delta t

where:

I is the impulse

F is the force exerted on the object

\Delta t is the time during which the force is applied

For the object in this problem, we have

F=106 N (force applied)

\Delta t= 15.6 s (time interval)

Therefore, the impulse experienced by the object is:

I=(106)(15.6)=1654 kg m/s

3 0
3 years ago
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