B 30 kg because
One quarter =1/2
Kg=60
1/2 of Kg
1/2*60
30 kg
The strength of the electric field on the point charge at this distance will be 4000 V/m.
<h3>What is the strength of the electric field?</h3>
The strength of the electric field is the ratio of electric force per unit charge.
The given data in the problem is;
Qis the unit charge = 4.0 × 10⁻⁶ C
E is the strength of the electric field
R is the distance from point charge = 3 m
The strength of the electric field is;

Hence, the strength of the electric field on the point charge at this distance will be 4000 V/m.
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Answer:
2870 N
Explanation:
There are three forces on the mattress. Weight of the mattress, weight of the person, and buoyancy.
∑F = ma
B - mg - Mg = 0
Buoyancy is equal to the weight of the displaced fluid.
ρVg - mg - Mg = 0
ρV - m = M
Plugging in values:
M = (1000 kg/m³) (0.75 m × 2.25 m × 0.175 m) - 2 kg
M = 293 kg
The person's weight is therefore:
Mg = 293 kg × 9.8 m/s²
Mg = 2870 N
Answer:
1654 kg m/s
Explanation:
The impulse experienced by an object is equal to the product between the force exerted on the object and the time during which the force lasts:

where:
I is the impulse
F is the force exerted on the object
is the time during which the force is applied
For the object in this problem, we have
(force applied)
(time interval)
Therefore, the impulse experienced by the object is:
