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Margarita [4]
3 years ago
13

0.39 is 15% of what number

Mathematics
1 answer:
vlabodo [156]3 years ago
5 0
0.39/15x100 = 2.6 easy

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From a height of 50 meters above sea level on a cliff, two ships are sighted due west. The angles of depression are 61° and 28°.
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Answer:

The ships are 66 meters apart.

Step-by-step explanation:

For the sake of convenience, let us label ships A and B

As shown in the figure, the distances to the ships from right triangles.

The distance to the ship A is d_1 and it is given by

tan (61^o)= \dfrac{50}{d_1}

d_1=\dfrac{50}{tan (61^o)}

\boxed{d_1= 27.71m}

And the distance to the ship B is d_2 and is given by

tan (28^o)= \dfrac{50}{d_2}

d_2=\dfrac{50}{tan (28^o)}

\boxed{ d_2=94.04m}

Therefore, the distance d between the ships A and B is

d= d_2-d_1=94.04-27.7\\\\\boxed{d=66m}

In other words, the ships are 66 meters apart.

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Find the area of the shaded region in square units. Show your reasoning.
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Answer:

40 square units

Step-by-step explanation:

First of all, lets say that square has side l, so, the area unit is l^2

the diagonal's square is l\sqrt{2}

CALCULATION OF TRIANGLES'S AREA (there are 4 triangles)

A_{triangles}=4*base*heigh*0.5=2*(l\sqrt{2} )(2l\sqrt{2} )=8l^2

CALCULATION OF MAIN SQUARE AREA

A_{square}=side*side=(4\sqrt{2} l)(4\sqrt{2} l)=32l^2

TOTAL AREA

A_{total}=A_{triangles}+A_{square}=8l^2+32l^2=40l^2

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3 years ago
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