3 years ago

WORTH 8 POINTSWhat is the area of a rectangle with side lengths of 6/8 meter and 4/ 10 meter?

Mathematics

1 answer:

miv72 [106K]3 years ago

5 0

Answer:

3/10 (see picture for work)

<h2>Correction:</h2>

I meant to write down $a=l*h$ , not $a=b*w$ .

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The diagram shows a square ABCD with sides of length 20cm. it also shows a semi circle and an arc circle AB is the diameter of t

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Answer:

Area of Shaded Region $=50\pi$ cm^2$

Area of Semicircle $=50\pi$ cm^2$

$\dfrac{\text{Area of Shaded region}}{\text{Area of Square}}=\dfrac{ \pi}{8}$

Step-by-step explanation:

Area of Shaded Region = Area of Sector - Area of Semicircle

<u>Area of Sector</u>

Radius of the sector =20cm

$=\frac{90}{360}X\pi *20^2\\ =100\pi cm^2$

<u>Area of Semicircle</u>

Since AB is the diameter of the semicircle

Radius of the Semicircle=20/2=10cm

Area of semicircle

$=\frac{\pi r^2}{2}\\ =\frac{\pi *10^2}{2}\\=50\pi cm^2$

Therefore, area of Shaded Region

$=100\pi -50 \pi\\=50\pi$ cm^2$

Area of Square =20 X 20 $=400 cm^2$

$\dfrac{\text{Area of Shaded region}}{\text{Area of Square}} \\=\dfrac{50 \pi}{400} \\=\dfrac{ \pi}{8}$

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