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AleksAgata [21]
3 years ago
8

The gravitational force between two objects increases as​

Physics
1 answer:
Misha Larkins [42]3 years ago
8 0

Answer: Their masses increases or the distance <u>between</u> them decreases

Explanation:

According to Newton's law of Gravitation, the gravitational force F exerted between two bodies of masses m1 and m2  and separated by a distance r  is equal to the <u>product of their masses</u> and inversely proportional to the <u>square of the distance</u>:

F=G\frac{(m1)(m2)}{r^2}   (1)

Where G is the Gravitational Constant

As we can see, if <u>one body increases its mass</u> or if <u>both bodies increase their mass</u>, the gravitational force will<u> increase</u> as well.

In addition, is the <u>distance between the two bodies is decreased</u>, the  <u>gravitational force will increase</u>.

Therefore:

The gravitational force between two objects increases as​ <u>their mass increases or the distance between them decreases.</u>

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A) The resultant force is 30.4 N at 25.3^{\circ}

B) The resultant force is 18.7 N at 43.9^{\circ}

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A)

In order to find the resultant of the two forces, we must resolve each force along the x- and y- direction, and then add the components along each direction to find the components of the resultant.

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Resolving each force:

F_{1x}=F_1 cos \theta = (20)(cos 0)=20 N\\F_{1y}=F_1 sin \theta =(20)(sin 0)=0 N

F_{2x}=F_2 cos \theta = (15)(cos 60)=7.5 N\\F_{2y}=F_2 sin \theta =(15)(sin 60)=13.0 N

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B)

In this case, the 15 N is applied in the opposite direction to the 20 N force. Therefore we need to re-calculate its components, keeping in mind that the angle of the 15 N force this time is

\theta=180^{\circ}-60^{\circ}=120^{\circ}

So we have:

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And the direction is:

\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{13.0}{13.5})=43.9^{\circ}

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brainly.com/question/4945130

brainly.com/question/5892298

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