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AleksAgata [21]
3 years ago
8

The gravitational force between two objects increases as​

Physics
1 answer:
Misha Larkins [42]3 years ago
8 0

Answer: Their masses increases or the distance <u>between</u> them decreases

Explanation:

According to Newton's law of Gravitation, the gravitational force F exerted between two bodies of masses m1 and m2  and separated by a distance r  is equal to the <u>product of their masses</u> and inversely proportional to the <u>square of the distance</u>:

F=G\frac{(m1)(m2)}{r^2}   (1)

Where G is the Gravitational Constant

As we can see, if <u>one body increases its mass</u> or if <u>both bodies increase their mass</u>, the gravitational force will<u> increase</u> as well.

In addition, is the <u>distance between the two bodies is decreased</u>, the  <u>gravitational force will increase</u>.

Therefore:

The gravitational force between two objects increases as​ <u>their mass increases or the distance between them decreases.</u>

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A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that incre
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Complete Question

A flat loop of wire consisting of a single turn of cross-sectional area 8.00 cm2 is perpendicular to a magnetic field that increases uniformly in magnitude from 0.500 T to 1.60 T in 0.99 s. What is the resulting induced current if the loop has a resistance of 1.20  \ \Omega

Answer:

The current is   I =  0.0007 41 \ A

Explanation:

From the question we are told that

   The  area is  A = 8.00 \ cm^2  = 8.0 *10^{-4} \  m^2

   The initial magnetic field at t_o = 0 \ seconds  is B_i = 0.500 \ T

   The magnetic field at t_1 = 0.99 \ seconds is  B_f  = 1.60 \ T

     The resistance is  R = 1.20  \ \Omega

Generally the induced emf is mathematically represented as

      \epsilon  =  A * \frac{B_f - B_i }{ t_f - t_o }

=>   \epsilon  =  8.0 *10^{-4} * \frac{1.60  - 0.500 }{ 0.99- 0  }

=>   \epsilon  = 0.000889 \ V

Generally the current induced is mathematically represented as

     I = \frac{\epsilon}{R }

=>  I = \frac{0.000889}{ 1.20 }  

=>  I =  0.0007 41 \ A  

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