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Gekata [30.6K]
2 years ago
8

How do you calculate a bearing angle and its equivalent angle?

Physics
1 answer:
denis-greek [22]2 years ago
4 0

Explanation:

A bearing if an angle is measured clockwise from north direction.

e.g Below the bearing of B from A is 025. (3 figures are always given). the bearing of A from B is 205°.

You might be interested in
An unknown element is found to have two naturally occurring isotopes, 200X and 210X with atomic masses of 200.028 and 210.039 re
Kruka [31]

Answer:

The average atomic mass of X is 206.0346

Explanation:

Atomic mass of 200X = 200.028

% abundance of 200X = 40% = 40/100 = 0.4

Atomic mass of 210X = 210.039

% abundance of 210X = 100% - 40% = 60% = 60/100 = 0.6

Average atomic mass of X = (0.4×200.028) + (0.6×210.039) = 80.0112 + 126.0234 = 206.0346

5 0
3 years ago
Newton's first law of motion is also called the law of acceleration true or false
kotykmax [81]
False. Newton first is also called the law of intertia
4 0
3 years ago
Why do we add alcohol/ethanol to the leaf once it is boiled?
hichkok12 [17]

Answer:

Complete answer: We boil the leaf in alcohol when we are checking it for starch to eradicate chlorophyll, which is the green pigment present in leaves. ... Hence to dissolve the chlorophyll or the green pigment present in the leaf we boil the leaf in alcohol when we are testing it for starch.

Hope this helps! Have a great day!

4 0
3 years ago
True or False <br> Most magnets are made<br> from 100% aluminum
bazaltina [42]

Answer:

True

I hope it helps.

4 0
2 years ago
Read 2 more answers
A coil of 160 turns and area 0.20 m2 is placed with its axis parallel to a magnetic field of initial magnitude 0.40 T. The magne
ser-zykov [4K]

Answer:

The rate at which power is generated in the coil is 10.24 Watts

Explanation:

Given;

number of turns of the coil, N = 160

area of the coil, A = 0.2 m²

magnitude of the magnetic field, B = 0.4 T

time for field change = 2 s

resistance of the coil, R =  16 Ω

The induced emf in the coil is calculated as;

emf = dΦ/dt

where;

Φ is magnetic flux = BA

emf = N (BA/dt)

emf = 160 (0.4T x 0.2 m²)/dt

emf = 12.8 V/s

The rate power is generated in the coil is calculated as;

P = V²/ R

P = (12.8²) / 16

P = 10.24 Watts

Therefore, the rate at which power is generated in the coil is 10.24 Watts

8 0
3 years ago
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