1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
defon
3 years ago
13

Is work being done on a barbell when a weight lifter is holding the barbell over his head?

Physics
1 answer:
Artemon [7]3 years ago
5 0

Answer:

Because in order for work to be done on an object, the object must be moving. Why isn't work being done on a barbell when a weight lifter is holding the barbell over his head? Work is maximized when force is applied in the same direction that the object is moving. ... In order to do work faster, more_is required.

You might be interested in
5. During an anti-bullying club meeting after school, a student mentions that a new student has joined your class at school. The
Oksana_A [137]

Answer:

a. Constant gossiping, and talking negative about a student could cause them to feel very very ill about their beliefs, their familly, school, clothes, etc. this  scenario will make the student feel alienated.

b. The club should advise the students that they should not participate in these talks, allow them into their groups, and should try to talk people out of those conversations.

c. The advice will keep several kids pull away from talking negatively about the kid, help stop the ill intended gossip, and hopefully make them feel better.

5 0
3 years ago
During the class prize-giving ceremony, Anand clapped his hands hard while Kumar clapped his hands softly. Everybody could hear
algol13

Answer:

C - higher volume

Explanation:

The pitch or frequency of sound that an object can produce depends upon its size and configuration . The shape of hand of all are same so the frequency of sound produced by hands of all will be almost same . Hence frequency of sound produced by the hands of Anand and Kumar would have been almost the same .

But the intensity of sound produced by them would have been different . Intensity represents energy a sound carries . Hard hitting clap will produce sound of higher intensity . Intensity of sound is also called high volume sound . So Kumar's clap will carry greater energy and hence greater volume of sound .

3 0
3 years ago
This is a Science question pls help give 15 coins for answer
Vlad1618 [11]

Answer:

<u>Conservation</u>: using less water

<u>Xeriscaping</u>: replanting your yard with plants that do not require great amounts of water

<u>Desalination</u>: process of removing salt from water so that it can be used for consumption

<u>Water Budget</u>: finite amount of usable water available

<u>Potable</u>: water that is safe to use a drink

7 0
3 years ago
Read 2 more answers
A 332 kg mako shark is moving in the positive direction at a constant velocity of 2.30 m/s along the bottom of a sea when it enc
Digiron [165]

To solve this problem we will apply the concepts related to the conservation of momentum. By definition we know that the initial moment must be equivalent to the final moment of the two objects therefore

p_1 = p_2

m_1u_1+m_2u_2 = m_1v_1+ m_2v_2

Here,

m_{1,2} = Mass of each object

u_{1,2} = Initial velocity of each object

v_{1,2}= Final velocity of each object

Since the initial velocity relative to the metal tank is at rest, that velocity will be zero. And considering that in the end, the speed of the two bodies is the same, the equation would become

m_1u_1 = (m_1+m_2)v_f

Rearranging to find the velocity,

v_f = \frac{m_1u_1}{ (m_1+m_2)}

Replacing we have that,

v_f = \frac{(332)(2.3)}{ (332+19.5)}

v_f = 2.17 m/s

Therefore the velocity of the shark immediately after it swallows the tank is 2.17m/s

4 0
3 years ago
The pressure P (in kilopascals), volume V (in liters), and temperature T (in kelvins) of a mole of an ideal gas are related by t
stich3 [128]

Answer:

\dfrac{dV}{dt} = -0.466 m^3/s

Explanation:

given,

P (in kilo pascals),         volume V (in liters),        temperature T (in kelvins)

P V = 8.31 T

Rate of increase the temperature =  0.1 K/s

temperature = 285 K

Pressure = 18 kPa

increasing at the rate of 0.07 k Pa/s

Rate at which volume is changing = ?

V = 8.31 \dfrac{T}{P}

\dfrac{dV}{dt} = 8.31 \dfrac{P\dfrac{dT}{dt}-T\dfrac{dP}{dt}}{P^2}

\dfrac{dV}{dt} = 8.31 \dfrac{18 \times 0.1-285\times 0.07}{18^2}

\dfrac{dV}{dt} = 8.31 \dfrac{-18.15}{324}

\dfrac{dV}{dt} = -0.466 m^3/s

7 0
3 years ago
Other questions:
  • Please help on this one?
    12·1 answer
  • Please help me with these 3 questions!!
    6·1 answer
  • Four students measure the mass of a standard mass that has an accepted value of 150.0 g. They post their results in a table.
    15·1 answer
  • What is the easiest way to increase the magnetic force acting on the rotor in an induction motor?
    11·1 answer
  • List 3 objects that would sink in water &amp; 3 object that would float in water :)​
    6·2 answers
  • You could use an elevator or stairs to lift a box to the tenth floor. Which has greater energy? Why?
    15·1 answer
  • The net force on an object is 200 N. The object accelerates at 10 m/s? What is the mass of the object ?
    5·1 answer
  • HELP I'll Mark as brainliest!
    6·1 answer
  • Simple harmonic motion occurs when an object is displaced from its stable equilibrium position and the force or torque pushing i
    14·1 answer
  • I really need help, whats 2+2
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!