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defon
3 years ago
13

Is work being done on a barbell when a weight lifter is holding the barbell over his head?

Physics
1 answer:
Artemon [7]3 years ago
5 0

Answer:

Because in order for work to be done on an object, the object must be moving. Why isn't work being done on a barbell when a weight lifter is holding the barbell over his head? Work is maximized when force is applied in the same direction that the object is moving. ... In order to do work faster, more_is required.

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At resonance, a driven rlcrlc circuit has vcvc = 5.0 vv , vrvr = 8.0 vv , and vlvl = 5.0 vv . part a what is the peak voltage ac
Simora [160]

The real peak voltage is 120/0.707 = 170 V.

The peak voltage is the highest point or voltage value in any voltage waveform. A power quality issue arises when Pulse Width Modulation (PWM) devices, such as variable frequency drives, are added to a power system with a peak voltage equal to the square root of two times the RMS voltage. The peak voltage, for instance, if the RMS voltage is 85 V. The average voltage and maximum voltage of AC power coming from the wall are both about 110 V. Therefore, the real peak voltage is 120/0.707 = 170 V. The sinusoid's amplitude is divided in half by this. Peak-to-peak voltage (Vp-p), also known as the total amplitude, is 340 V, or twice the peak voltage.

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4 0
2 years ago
What SI units are combined to describe energy
Ratling [72]

Answer:

SI unit for energy is Joules.  

in base units it will be:

1 J = 1 N·m = <u>1 kg·m²/s²</u>

6 0
1 year ago
A cylinder containing an ideal gas has a volume of 2.6 m3 and a pressure of 1.5 × 105 Pa at a temperature of 300 K. The cylinder
frozen [14]
<h2>Answer:13.5\times 10^{8} joules</h2>

Explanation:

From the first law of thermodynamics,

ΔQ=ΔU+W

Where Q is the heat given to the gas,

U is the internal energy of the gas,

W is the workdone by the gas.

When pressure is constant,

\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}

V_{2}=\frac{2.6\times 900}{300}=7.8m^{3}

When pressure is constant,W=PΔV

Where P is pressure and V is the volume of the gas.

Given P=1.5\times 10^{5}Pa

ΔV=7.8-2.6=5.2m^{3}

So,W=1.5\times 10^{5}\times 5.2=7.8\times 10^{5}J

Given that ΔU=6\times 10^{5}

So,ΔQ=6\times 10^{5}+7.8\times 10^{5}=13.8\times 10^{5}J

5 0
4 years ago
What is the input of energy for a device that provides 50 units of useful energy and has an efficiency of 0.55?
ki77a [65]

If that's the case, then  

                          50 units = 0.55 x the input energy

Divide each side by  0.55 :        

                   50 units/0.55  =  the input energy = 

                              <span> 90 and 10/11 units</span>
3 0
3 years ago
You cover the following displacements every day going to school: d1=50 m, E and d2=95 m, N. You do this for 12 minutes. a) What
puteri [66]

The speed will be 0.2 m/s and the velocity will be 0 m/s.

Speed = Total Distance / Total time

We have given total distance as ( 50 + 95 ) metres and total time as 12 minutes or we can say 720 seconds.

Speed = 145/ 720 m/s

Speed = 0.2 m/s

Velocity = Total Displacement / Total time

As the initial and final is the home, hence the net displacement is 0 in that case.

In this case also the total time we have given is 12 minutes or we can say 720 seconds.

Velocity = 0 / 720 m/s

Velocity = 0 m/s

So to conclude with we can say that the speed is 0.2 m/s and the velocity is 0 m/s.

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5 0
2 years ago
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