What is the formula to determine the mass of the Earth?
1 answer:
You might be interested in
Answer:
v_y = 14.55 m/s
Explanation:
given,
height at which gull is flying = 10.80 m
speed of the gull = 6 m/s
acceleration due to gravity = 9.8 m/s²
Relative to the seagull, the x-speed is 0,
because the seagull has the same x-speed.
Only the y-speed counts:
v_y = 14.55 m/s
hence, the speed at which the clam smash the rock is v_y = 14.55 m/s
Answer:
966.22 mph
Explanation:
Velocity of plane with respect to wind (Vp,w)= 612 mph east
velocity of wind with respect to ground, (Vw,g) = 362 mph at 15° North of
east
Write the velocities in vector form
Use the formula for the relative velocity
Where, V(p,w) is the velocity of plane with respect to wind
V(p,g) is the velocity of plane with respect to ground
V(w,g) is the velocity of wind with respect to ground
So,
Magnitude of velocity of lane with respect to ground
V(p,g) = 966.22 mph
Answer:
y = x tan θ - (g / 2v₀² cos² θ) x²
Explanation:
An equation is called a general formula that relates the position on the x-axis and the height on the body's axis.
Let's write the position on each axis
X axis. No acceleration
x = v₀ₓ t
Y Axis. There is the acceleration of gravity
y = t - ½ g t²
Let's clear the time in the first equation and substitute in the second
y = v₀ sin θ (x / v₀ₓ) - ½ g (x / v₀ₓ)²
y = v₀ sin θ / v₀ cos θ x - ½ g x² / v₀² cos² θ
y = x tan θ - (g / 2v₀² cos² θ) x²
This is the trajectory equation in projectile launching
Answer:
The new time period is
Explanation:
From the question we are told that
The period of oscillation is
The new length is
Let assume the original length was
Generally the time period is mathematically represented as
Now I is the moment of inertia of the stick which is mathematically represented as
So
Looking at the above equation we see that
=>
=>
=>