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3 years ago

13

changes to OSHA's regulations in 2013 require chemical information be provided via the _______ format. a) safety data sheets b)

classification and labeling chemicals c) globally safety data sheets

1 answer:

Talja [164]3 years ago

8 0

Don't listen to the other guy I just took the test and got it wrong because of him..

I re-took it and the correct answer is

A) Safety Data Sheets (SDS)

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Please help in physics

Minchanka [31]

As there is no postive or negative assigned so
Initial velocity= -2.8759
Displacement= 0.5at^2+ut
= 0.5(-1.77)(3.33)^2+(-2.8759)(3.33)=-19.4m

4 0

3 years ago

1. Is this circuit SERIES or PARALLEL?

Setler79 [48]

Answer:

Series

Explanation:

Because I listen to my science teacher

3 0

3 years ago

A person walks into a room that has, on opposite walls, two plane mirrors producing multiple images. Find the distances from the

Lapatulllka [165]

Answer:13.2,41.4,82.8 ft

Explanation:

Given Person is 6.60 ft from the left hand side mirror

Since the focal length of plane mirror is infinity therefore image and object are equidistant from mirror

Distance of first image on left mirror is

$d_1=6.6+6.6=13.2 ft$

i.e. image is 13.2 ft away from object

Second image

Now the right mirror forms the image of object at distance of 14.1 ft right from right mirror so its image is formed in left mirror at a distance of 34.8 from left mirror

so image distance from person is

$d_2=34.8+6.6=41.4 ft$

Third image now form image of second image is formed on right mirror at a distance of 55.5 right from right mirror

and its mirror image is formed on left mirror at a distance of 76.2 left

from left mirror

$d_3=76.2+6.6=82.8 ft$

8 0

3 years ago

32. A forest ranger. 35 meters above the ground in a

Sphinxa [80]

Answer:

x = 102.33 m

Explanation:

Given that,

Position where a forest ranger stands is 35 m above the ground. The angle of depression to the base of the fire is 20. We need to find how far from the tower is the fire.

Let the distance is x. We can find x using trigonometry as follows :

$\sin\theta=\dfrac{\text{perpendicular}}{\text{hypotenuse}}\\\\\sin(20)=\dfrac{35}{x}\\\\x=\dfrac{35}{\sin(20)}\\\\x=102.33\ m$

Hence, the fire is at a distance of 102.33 m from the fire.

8 0

3 years ago

You pull a suitcase along the floor by exerting 43N at an angle. The force of friction is 27 N and the suitcase moves at a const

Mumz [18]

The angle of the force is $51.1^{\circ}$

Explanation:

To solve this problem, we can apply Newton's second law along the horizontal direction of motion of the suitcase:

$\sum F_x = ma_x$

where

$\sum F_x$ is the net force along the x-axis

m is the mass of the suitcase

$a_x$ is the acceleration along the x-axis

The suitcase is moving at constant speed, so the acceleration is zero:

$a_x=0$

Therefore the net force must also be zero:

$\sum F_x = 0$ (1)

We have two forces acting along the horizontal direction:

- The component of the push (forward) in the horizontal direction, $F cos \theta$ , with

F = 43 N

$\theta$ = angle of the force with the horizontal

- The force of friction, $F_f = 27 N$ , backward

So the net force can be written as

$\sum F_x = F cos \theta - F_f$ (2)

Combining (1) and (2),

$F cos \theta - F_f = 0$

And so we can find the angle:

$\theta = cos^{-1}(\frac{F_f}{F})=cos^{-1}(\frac{27}{43})=51.1^{\circ}$

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

8 0

3 years ago