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Grace [21]
3 years ago
13

A 243 mL cup of whole milk contains about 45 mg of cholesterol. Express the cholesterol concentration of the milk in kilograms p

er cubic meter (kg/m^3).
Physics
1 answer:
timama [110]3 years ago
5 0

Answer: 0.1851 \frac{kg}{m^{3}}

Explanation:

We have this concentration in units of mg/ml:

\frac{45 mg}{243 ml}

And we need to express it in kg/m^{3}, knowing:

1 ml= 1 cm^{3}

1 m^{3}= (100 cm) ^{3}

1g = 1000 mg

1 kg = 1000 g

Hence:

\frac{45 mg}{243 cm^{3}} \frac{1 g}{1000 mg} \frac{1 kg}{1000 g} \frac{(100 cm) ^{3}}{1 m^{3}}=0.1851 \frac{kg}{m^{3}}

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inn [45]
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7 0
3 years ago
What is the frequency of a wave with a wavelength of 12 meters and a velocity of 4 m/s?
trasher [3.6K]

Answer:

0.33 hz

Explanation:

the formula for the frequency in this situation is f=v/wavelength

8 0
3 years ago
A 5 kg fish swimming at 1 m/s swallows an absentminded 500 g fish swimming toward it at a velocity that brings both fish to a ha
AlexFokin [52]

To solve this problem we will apply the concepts related to the conservation of momentum. Momentum is defined as the product between mass and velocity of each body. And its conservation as the equality between the initial and final momentum. Mathematically described as

m_1u_1+m_2u_2 = (m_1+m_2)v_f

Here

m_1 = Mass of big fish

m_2 = Mass of small fish

v_1 = Velocity of big fish

v_2 = Velocity of small fish

v_F = Final Velocity

The big fish eats small fish and the final velocity is zero. Rearrange the equation for the initial velocity of small fish we have

m_1u_1=-m_2u_2

u_2 = -\frac{m_1u_1}{m_2}

Replacing we have,

u_2 = -\frac{(5kg)(1m/s)}{0.5kg}

u_2 = -10m/s

The negative sign indicates that the small fish is swimming in the direction opposite to that of the big fish.

Therefore the speed of the small fish is 10m/s

8 0
3 years ago
sara and tory are out fishing on the lake on a hot summer day when they both decide to go for a swim. sara dives off the front o
crimeas [40]

Here it is an application of Newton's III law

as we know by Newton's III law that every action has equal and opposite reaction

So here as we know that two boys jumps off the boat with different forces

from front side of the boat the boy jumps off with force 45 N which means as per Newton's III law if boy has a force of 45 N in forward direction then he must apply a reaction force on the boat in reverse direction of same magnitude

So boat must have an opposite force on front end with magnitude 45 N

Now similar way we can say

from back side of the boat the boy jumps off with force 60 N which means as per Newton's III law if boy has a force of 60 N in backward direction then he must apply a reaction force on the boat in reverse direction of same magnitude

So boat must have an opposite force on front end with magnitude 60 N

So here net force due to both jump on the boat is given by

F_{net} = F_1 - F_2

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F_{net} = 15 N

so boat will have net force F = 15 N in forward direction due to both jumps

3 0
3 years ago
3. What exerts a greater force on the table of 2 kg book lying flat or a 2 kg book on its
Darina [25.2K]

Answer:

A book on its side exerts a greater force.

Explanation:

Pressure = Force / Area

Assuming that 1kg = 10N

2kg = 20N

Area of book lying flat = 0.3m × 0.2m

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Pressure of book lying flat = 20N / 0.6m²

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Area of book on its side = 0.2m × 0.05m

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Pressure of book on its side = 20N / 0.01m²

                                               = 2000Pa (1 s.f.)

Since 2000Pa (1 s.f.) > 30Pa (1 s.f.), a book on its side applies greater pressure than lying flat.

5 0
2 years ago
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