Answer:
The atoms have the same chemical symbol.
Manipulated variable: the types of soil
Responding variable: how much t the plants grow
<span>To solve this we need to balance the equations first.
So Hg + S --> HgS is balanced
One mole of Hg requires one mole of S to form one mole of HgS.
Number of moles of Sulphur = mass/ molar mass = 157/32 = 4.906
So 4.90 moles of S reacts with 4.90 moles of Hg.
Hence there are 4.90 moles of 4.90 of Hg.
Mass = number of moles * molar mass of Hg
Mass = 4.906 * 200.59 = 982.891g</span>
The weight/weight percent(%w/w) of NaCl in solution : 33.03%
<h3>Further explanation</h3>
Given
Mole fraction of NaCl : 0.132
Required
The weight/weight percent of NaCl
Solution
1 mol solution : 0.132 mol NaCl + 0.868 mol H₂O
mass NaCl :

mass H₂O :

Total mass = 7.714 + 15.64 = 23.354 g

Answer: The molecular formula will be 
Explanation:
If percentage are given then we are taking total mass is 100 grams.
So, the mass of each element is equal to the percentage given.
Mass of C = 40.0 g
Mass of O = 53.3 g
Mass of H = 6.66 g
Step 1 : convert given masses into moles.
Moles of C =
Moles of O =
Moles of H =
Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.
For C =
For O =
For H = 
The ratio of C : O : H = 1: 1: 2
Hence the empirical formula is
The empirical weight of
= 1(12)+1(16)+2(1)= 30g.
The molecular weight = 60 g/mole
Now we have to calculate the molecular formula.
The molecular formula will be=