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Nadusha1986 [10]
3 years ago
10

Will a parachute slow a skydiver more at a very high altitude or a lower altitude?

Chemistry
1 answer:
kompoz [17]3 years ago
5 0
The answer is High altitude
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If 6 g of element k combine with 17 g of element l, how many grams of element k combine with 85 g of element l?
Ede4ka [16]
Hope this helps you.

5 0
3 years ago
Wind erosion
Agata [3.3K]

Answer:

removes the fertile B horizon of soil

Explanation:

<em>Wind erosion has the capacity to remove the fertile B horizon of the soil.</em>

The term wind erosion generally refers to the capacity of high-magnitude wind to cause damages to the terrestrial environment. Soils can get their topmost layers removed by a strong wind if there are no barriers such as vegetation to break the speed of the wind.

The topmost layers in most cases consist of humus and the fertile minerals from parent materials. When the topmost layer is lost, the soil becomes unproductive for agriculture.

8 0
3 years ago
If 4.12 l of a 0.850 m-h3po4 solution is be diluted to a volume of 10.00 l, what is the concentration of the resulting solution?
statuscvo [17]

The process in which the concentration of the solution is lessened  by the addition of water is said to be dilution and equation of dilution relates the initial concentration and volume of stock solution with the final concentration and volume of the solution.

Formula is given by:

C_{1}V_{1}=C_{2}V_{2}   (1)

where,

C_{1} is the initial concentration

V_{1} is the initial volume

C_{2} is the final concentration

V_{2} is the final volume

Now,

C_{1} = 0.850 M

V_{1} = 4.12 L

C_{2}  =?

V_{2} = 10.00 L

Substitute the give values in formula (1),

0.850 M\times 4.12L=C_{2}\times 10.00 L

C_{2} =\frac{0.850 M\times 4.12L}{10.00 L}

= 0.3502 M

Thus, the final concentration of theH_{3}PO_{4} solution = 0.3502 M












5 0
2 years ago
Consider this equilibrium: COCl2(g) CO(g) + Cl2(g) Keq = 8.1 x 10-4. What is true for this system?
fiasKO [112]
Answer is: [COCl₂] > [CO][Cl₂]
Chemical reaction: COCl₂(g) ⇄ CO(g) + Cl₂(g); Keq = 8.1 x 10⁻⁴.
Keq = [CO] · [Cl₂] / [COCl₂]; equilibrrium constant of chemical reaction.
[CO] · [Cl₂] / [COCl₂] = 0,00081.
Equilibrium product concentration is much more less than equilibrium concentration of reactant.

6 0
2 years ago
Explain the three ways that machines can make work easier
mr Goodwill [35]
1. they work ways faster
2. you don't need 100 people making the same thing at once
3. its a better chance of not getting an injury
8 0
3 years ago
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