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Nadusha1986 [10]
4 years ago
10

Will a parachute slow a skydiver more at a very high altitude or a lower altitude?

Chemistry
1 answer:
kompoz [17]4 years ago
5 0
The answer is High altitude
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Atom A and Atom B have the same number of protons and neutrons, but they do not have the same nun ber of
Bogdan [553]

Answer:

The atoms have the same chemical symbol.

6 0
3 years ago
Eddie is performing an experiment. He asked the question what type of soil makes plants grow the fastest. He has four plants. He
Bezzdna [24]
Manipulated variable: the types of soil
Responding variable: how much t the plants grow
4 0
3 years ago
How many grams of mercury are needed to react completely with 157g of sulfur to form hgs?
Salsk061 [2.6K]
<span>To solve this we need to balance the equations first.
 So Hg + S --> HgS is balanced
 One mole of Hg requires one mole of S to form one mole of HgS.
 Number of moles of Sulphur = mass/ molar mass = 157/32 = 4.906
So 4.90 moles of S reacts with 4.90 moles of Hg.
Hence there are 4.90 moles of 4.90 of Hg.
 Mass = number of moles * molar mass of Hg
Mass = 4.906 * 200.59 = 982.891g</span>
8 0
3 years ago
Read 2 more answers
The mole fraction of NaCl in an
posledela

The weight/weight percent(%w/w) of NaCl in  solution : 33.03%

<h3>Further explanation</h3>

Given

Mole fraction of NaCl : 0.132

Required

The weight/weight percent of NaCl

Solution

1 mol solution : 0.132 mol NaCl + 0.868 mol H₂O

mass NaCl :

\tt 0.132\times 58.44 g/mol=7.714~g

mass H₂O :

\tt 0.868\times 18.016~g/mol=15.64~g

Total mass = 7.714 + 15.64 = 23.354 g

\tt \%NaCl=\dfrac{7.714}{23.354}\times 100\%=33.03\%

6 0
3 years ago
10 points!! Please give me work with it and I will mark as brainlist.
Georgia [21]

Answer: The molecular formula will be C_2H_4O_2

Explanation:

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of C = 40.0 g

Mass of O = 53.3 g

Mass of H = 6.66 g

Step 1 : convert given masses into moles.

Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{40.0g}{12g/mole}=3.33moles

Moles of O =\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{53.3g}{16g/mole}=3.33moles

Moles of H =\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{6.66g}{1g/mole}=6.66moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = \frac{3.33}{3.33}=1

For O =\frac{3.33}{3.33}=1

For H = \frac{6.66}{3.33}=2

The ratio of C : O : H = 1: 1: 2

Hence the empirical formula is COH_2

The empirical weight of COH_2 = 1(12)+1(16)+2(1)= 30g.

The molecular weight = 60 g/mole

Now we have to calculate the molecular formula.

n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}=\frac{60}{30}=2

The molecular formula will be=2\times CH_2O=C_2H_4O_2

8 0
3 years ago
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