Answer:
The concentration of chloride ion is 2.887 M.
Explanation:
Here we have a combination BaCl₂ and AlCl₃
1 mole BaCl₂ can produce 2 moles chloride ions as follows;
BaCl₂ → Ba²⁺ + 2Cl⁻
Therefore;
0.554 mole BaCl₂ can produce 2×0.554 moles chloride ions;
1 mole AlCl₃ can produce 3 moles chloride ions as follows;
AlCl₃ → Al³⁺ + 3Cl⁻
Therefore;
0.593 mole AlCl₃ can produce 3×0.593 moles chloride ions
Total concentration of chloride ions = 2×0.554 + 3×0.593 = 2.887 moles of Cl⁻ in 2×16.8 ml solution
The concentration of Cl⁻ is 2.887 M
