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Arte-miy333 [17]
3 years ago
12

How many of the carbon–carbon bonds in the compound have staggered conformers that are all equally stable?

Chemistry
2 answers:
Anon25 [30]3 years ago
8 0

Answer : The 3 carbons which are bonded to CH_{3} have equally stable staaggered conformers.

There are 3 identical atoms of hydrogens in 2-methylhexane molecule (refer attached figure)

Therefore any degree of rotation of 60 or 180 or 300 in C-C bond will give a stable conformer of the same energy.

The image is attached for the stable staggered conformation.

lyudmila [28]3 years ago
3 0
In stereoisomers, there are two classifications: staggered and eclipsed conformations. The staggered conformation is when the bonds are not symmetric. Eclipsed is less stable than the staggered conformation. It actually depends on the compound. For example, the ethane is drawn in the staggered conformation, which only has 1 C-C single bond.

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Answer:

For every 4 moles of NO created, 6 moles of H2O are created so the ratio is 4:6

Explanation:

You just need to balance the equation.

NH3 + O2 -> NO + H2O

1. I started with hydrogen; there's 3 on the left and 2 on the right. Multiply them together to find a number they both go into (3×2=6, but in this case 6 hydrogen on each side does not work so I doubled it so there is 12 hydrogen on each side).

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2. Now get equal amounts of nitrogen on each side. There's 4 nitrogen on the left side, and 1 on the right. Multiply the right by 4. Then you will have this:

4NH3 + O2 -> 4NO + 6H2O

3. Last thing you need to do is have the same amount of oxygen on both sides. On the left you have 2 and on the right you have 10. Get the left to 10 by multiplying it by 5.

Balanced: 4NH3 + 5O2 -> 4NO + 6H2O

In word form, for every reaction between 4 moles of ammonia and 5 moles of oxygen, 4 moles of nitric oxide and 6 moles of water will be created.

I hope this helps!

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