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3 years ago

5

In the drawing below, a boy with his shadow is standing beside a monument with its shadow. the drawing is not drawn to scale.

1 answer:

CaHeK987 [17]3 years ago

4 0

There exists the same question from other source that has the image of the drawing. Attached to this answer is the image.

To solve this, first we have to assume ratios.

Real Height / Shadow = 56 / 49
Real Height / 28 = 56 / 49
49 * h = 56 * 28
49h = 1568

Then, we have to divide both sides by 9
h = 32

Therefore, the obelisk is 32 ft

C is correct answer to this question.

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What is the slope of the line through the points (–3, 5) and (4, 5)? undefined 0 2 –2

Kazeer [188]

Finding the slope using two points:

The formula for slope is

$\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

In this case you have the points (-3, 5) and (4, 5):

$y_{2} =5\\y_{1} =5\\x_{2} =4\\x_{1} =-3$

^^^Plug these numbers into the formula for slope...

$\frac{5-5}{4 - (-3)}$

$\frac{0}{7}$

0

^^^This is your slope

Hope this helped!

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2 years ago

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Twice the difference of a number and 8 is 6<br><br> Write an equation using variable w

Sauron [17]

Answer:

8w-2=6

Step-by-step explanation:

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3 years ago

What point on the number line below represents the opposite of -4

Vinvika [58]

X is the opposite of -4

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3 years ago

Show that the following functions are probability density functions for some value of k and determine k. Then, determine the mea

lord [1]

Answer:

a) 17.5

b) 15.6

c) 13.3

d) 21.51

Step-by-step explanation:

The given function is equal to:

f(x)=kx^2

where

$\int\limits^y_0 {kx^{2} } \, =1$

where y=23

Clearing k=0.00025

a) $Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.00025x^{2} } \, dx =17.5$

b) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2}f(x) } \, dx-17.5^{2} =\int\limits^y_0 {x^{2} *0.00025x^{2} } \, dx -17.5^{2} =321.82-306.25=15.6$

c) The function is equal to:

f(x)=k(1+2x)

$\int\limits^y_0 {k(1+2x)} \, =1$

where y=20

k=0.0024

$Ex=\int\limits^y_0 {xf(x)} \, dx =\int\limits^y_0 {x*0.0024(1+2x)} \, dx =13.3$

d) $Vx=Ex^{2} -(Ex)^{2} =\int\limits^y_0 {x^{2} f(x)} \, dx -13.3^{2}=\int\limits^y_0 {x^{2} *0.0024(1+2x)} \, dx-13.3^{2} =198.4-176.89=21.51$

8 0

3 years ago

What value of x makes this equation true?<br> 5 -3 = +3<br> A 3<br> B -9<br> C -1<br> D 27

Anastasy [175]

Answer:

-1 I think

Step-by-step explanation:

5-3=2 and -1+3=2

4 0

2 years ago