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sashaice [31]
2 years ago
10

A 12-kg lead brick falls from a height of 1.9 m. (c) The brick falls onto a carpet, 2.0 cm thick. Assuming the force stopping it

is constant, find the average force the carpet exerts on the brick.
Physics
1 answer:
Genrish500 [490]2 years ago
8 0

Answer:

F = -11199.63 N

Explanation:

given,

mass of the brick = 12 Kg

height of the fall, h = 1.9 m

thickness of the carpet = 2 cm = 0.02 m

average force = ?

velocity of brick just before hitting mat

v = \sqrt{2gh}

v =\sqrt{2\times 9.81\times 1.9}

      v = 6.11 m/s

velocity of brick just before hitting ground= 6.11 m/s

final velocity = 0 m/s

using equation of motion for acceleration calculation.

 v² = u² + 2 a s

 0² = 6.11² + 2x a x 0.02

 a = -\dfrac{6.11^2}{0.04}

    a  =-933.3025 m/s²

now, average force is equal to

F = m a

F = 12 x (-933.3025)

F = -11199.63 N

negative sign represent the decelerating force.

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An object of mass 2 kg starts from rest and is allowed to slide down a
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Given that an object of mass 2 kg starts from rest and is allowed to slide down a frictionless incline so that its height changes by 20 m. 

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A 25kg chair initially at rest on a horizontal floor requires 165 N force to set it in motion. Once the chair is in motion, a 12
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