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vlada-n [284]
3 years ago
8

Which best explains how the diffraction pattern observed in Young’s experiment supports the wave theory of light?

Chemistry
2 answers:
olganol [36]3 years ago
4 0
<span>C. The pattern was caused by the interference of waves. </span>
Damm [24]3 years ago
3 0

<u>Answer:</u> The correct answer is option C.

<u>Explanation:</u>

The experiment performed by Thomas Young was named as double-slit experiment. In this experiment, he demonstrated the wave theory of the light.

In the experiment, he took a point source of light which illuminated two narrow adjacent slits on the screen and the image formed by the light were passed through the slits and was observed on the second screen.

The regions of dark and light regions were called as interference fringes which were caused by the constructive and the destructive interference of light waves.

Hence, he concluded that the pattern that was caused was due to the interference of the waves.

Therefore, the correct answer is Option C.

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Answer / explanation:

How does concentration affect boiling point of a solvent?

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The higher the concentration, the more higher the boiling point of a solvent.

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Answer:

Sample A is a mixture

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Explanation:

For sample A, we are told that the originally yellow solid was dissolved and we obtained an orange powder at the bottom of the beaker. Subsequently, only about 30.0 g of solid was recovered out of the 50.0g of solid dissolved. This implies that the solid is not pure and must be a mixture. The other components of the mixture must have remained in solution accounting for the loss in mass of solid obtained.

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An interpenetrating primitive cubic structure like that of CsCl with anions in the corners has an edge length of 664 pm. If the
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Answer:

the ionic radius of the anion r^- = 312.52 \ pm

Explanation:

From the diagram shown below :

The anion Cl^- is located at the corners

The cation Cs^+ is located at the body center

The Body diagonal length =  \sqrt{3 \ a }

∴ 2 \ r^+ \ + 2r^- \ = \sqrt{3 \ a}  \\ \\ r^+ +r^- = \frac{\sqrt{3}}{2} a

Given that :

\frac{r^+}{r^-} =0.84   (i.e the  ratio of the ionic radius of the cation to the ionic radius of

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0.84r^- \ + r^- \ = \frac{\sqrt{3}}{2}a  \\ \\  1.84 r^- = \frac{3}{2}a \\ \\ r^- = \frac{\sqrt{3}}{2*1.84}a

Also ; a =  664 pm

Then :

r^- = \frac{\sqrt{3} }{2*1.84}*664 \ pm\\ \\ r^- = 312.52 \ pm

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