All categories

3 years ago

When is potential energy transformed into kinetic energy

1 answer:

7 0

Kinetic energy is when an object is in motion
How I got my answer is really easy you simply just look at the answers and see which one says the object is in motion . Your answer would most likely be D

You might be interested in

HEEEEEEEEEEEEEEELLLLLLLLLLLLPPPPPPP!!!!!!! I WILL MARK BRAINLIEST IF YOU HELP!!!!THIS IS DUE SOON!

Hitman42 [59]

Answer:

An ice pack uses friction and the chemicals inside make it mix to make it cold

Explanation:

3 0

3 years ago

A student isolated 7.2 g of 1-bromobutane reacting equimolar amounts of 1-butanol (10 ml) and NaBr (11.1 g) in the presence of s

Alla [95]

Answer: The percent yield of the 1-bromobutane is 48.65 %

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For NaBr:

Given mass of NaBr = 11.1 g

Molar mass of NaBr = 103 g/mol

Putting values in equation 1, we get:

$\text{Moles of NaBr}=\frac{11.1g}{103g/mol}=0.108mol$

The chemical equation for the reaction of 1-butanol and NaBr is:

$\text{1-butanol + NaBr}\rightarrow \text{1-bromobutane}$

By Stoichiometry of the reaction

1 mole of NaBr produces 1 mole of 1-bromobutane

So, 0.108 moles of NaBr will produce = $\frac{1}{1}\times 0.108=0.108$ moles of 1-bromobutane

Now, calculating the mass of 1-bromobutane from equation 1, we get:

Molar mass of 1-bromobutane = 137 g/mol

Moles of 1-bromobutane = 0.108 moles

Putting values in equation 1, we get:

$0.108mol=\frac{\text{Mass of 1-bromobutane}}{137g/mol}\\\\\text{Mass of 1-bromobutane}=(0.108mol\times 137g/mol)=14.80g$

To calculate the percentage yield of 1-bromobutane, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of 1-bromobutane = 7.2 g

Theoretical yield of 1-bromobutane = 14.80 g

Putting values in above equation, we get:

$\%\text{ yield of 1-bromobutane}=\frac{7.2g}{14.80g}\times 100\\\\\% \text{yield of 1-bromobutane}=48.65\%$

Hence, the percent yield of the 1-bromobutane is 48.65 %

5 0

2 years ago

Is this a redox reaction? give evidence (many points plz answer) 2Mg + CO2 → 2MgO + C

Aleonysh [2.5K]

Answer:

$\boxed{yeah}$

Explanation:

$CO_2 \: is \: reduced \: to→C \: by \: 2M_g \: (the \: reducing \: agent): while \\ 2M_g \: is \: oxydized \: to→2M_gO \: by \: CO_2 \: (the \: oxydizing \: agent)$

6 0

2 years ago

Describe the process of crystallization.

dalvyx [7]

Crystallization is a process where a solid forms into a substance we call crystal, this happens from precipitating from a solution, freezing, and more

4 0

2 years ago

What is the molarity of 6 moles (mol) of NaCl dissolved in 2 L of water?

Mama L [17]

Answer:

C: $\frac{6 mol}{2 L}$