Answer:
f(x) = 3 cos (2Pi / period value ; x )+ 2
or see answer using 2 as the period see answer in bold below.
Step-by-step explanation:
cosine function amplitude of 3 is A = 3
The period is used to find B
You need to show period value as the denominator and work out from there with 2PI as a function numerator to show as 2pi / period can be a data angle
C is the adding value.
Acos (Bx) + C
A = 3
Bx = 2 pi / period
C = + 2
However f 2 is also the period found
then we just plug in 2 to above formula
f(x) = 3 cos (2Pi / 2 ; x )+ 2
f(x) = 3cos (x pi) + 2
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To check whether a function is odd or even, we simply substitute the argument by its negative version, namely "x" by "-x".
if the expression simplifies to resemble the original expression, that simply means the expression is
even. If it resembles the original negative expression, is
odd.
well, that doesn't look like the original
- 2x³ - 9, so is not
even.
and -f(x) would be
2x³ + 9, and that doesn't look like either, so is not
odd.
thus is neither.
Answer:
Remember if cosecθ=1/sinθ
sinθ×cosecθ=sinθ×1/sinθ=1
CMIIW
